Chapter 1, Problem 1.101QP

(a)

Interpretation Introduction

Interpretation:

Given $\text{3}\text{.0}\text{g}$ has to be converted to pounds ($\text{lb}$).

Explanation of Solution

Given, $\text{3}\text{.0}\text{g}$

  $\begin{array}{l}\text{1}\text{lb}\text{=}\text{454}\text{g}\\ \text{=}\text{3}\text{.0}\text{g}\text{×}\frac{\text{1}\text{lb}}{\text{454}\text{g}}\\ \text{=}\text{0}\text{.006}\text{lb}\end{array}$

(b)

Interpretation Introduction

Interpretation:

Given $\text{3}\text{.0}\text{g}$ has to be converted to ounce ($\text{oz}$).

Explanation of Solution

Given, $\text{3}\text{.0}\text{g}$

  $\begin{array}{l}\text{1}\text{lb}\text{=}\text{454}\text{g}\\ \text{=}\text{3}\text{.0}\text{g}\text{×}\frac{\text{1}\text{lb}}{\text{454}\text{g}}\\ \text{=}\text{0}\text{.006}\text{lb}\\ \text{1}\text{lb}\text{=}\text{16}\text{oz}\\ \text{=}\text{0}\text{.006}\text{lb}\text{×}\frac{\text{16}\text{oz}}{\text{1}\text{lb}}\\ \text{=}\text{0}\text{.096}\text{oz}\end{array}$

(c)

Interpretation Introduction

Interpretation:

Given $\text{3}\text{.0}\text{g}$ has to be converted to kilograms ($\text{kg}$).

Explanation of Solution

Given, $\text{3}\text{.0}\text{g}$

  $\begin{array}{l}\text{1}\text{kg}\text{=}{\text{10}}^{\text{3}}\text{g}\\ \text{=}\text{3}\text{.0}\text{g}\text{×}\frac{\text{1}\text{kg}}{{\text{10}}^{\text{3}}\text{g}}\\ \text{=}\text{0}\text{.003}\text{kg}\end{array}$

(d)

Interpretation Introduction

Interpretation:

Given $\text{3}\text{.0}\text{g}$ has to be converted to centigrams ($\text{cg}$).

Explanation of Solution

Given, $\text{3}\text{.0}\text{g}$

  $\begin{array}{l}\text{1}\text{cg}\text{=}{\text{10}}^{\text{-2}}\text{g}\\ \text{=}\text{3}\text{.0}\text{g}\text{×}\frac{\text{1}\text{cg}}{{\text{10}}^{\text{-2}}\text{g}}\\ \text{=}\text{300}\text{cg}\end{array}$

(e)

Interpretation Introduction

Interpretation:

Given $\text{3}\text{.0}\text{g}$ has to be converted to milligrams ($\text{mg}$).

Explanation of Solution

Given, $\text{3}\text{.0}\text{g}$

  $\begin{array}{l}\text{1}\text{mg}\text{=}{\text{10}}^{\text{-3}}\text{g}\\ \text{=}\text{3}\text{.0}\text{g}\text{×}\frac{\text{1}\text{mg}}{{\text{10}}^{\text{-3}}\text{g}}\\ \text{=}\text{3000}\text{mg}\end{array}$