Do the following metric system conversions by changing only the power of 10 . For example, convert 2.5 L to mL : 2.5 L = 2.5 × 10 3 mL a. Convert 4.5 km to mm b. Convert 6.0 × 10 6 mg to g c. Convert 9.86 × 10 15 m to km d. Convert 1.91 × 10 − 4 kg to mg e. Convert 5.0 ng to mg
Do the following metric system conversions by changing only the power of 10 . For example, convert 2.5 L to mL : 2.5 L = 2.5 × 10 3 mL a. Convert 4.5 km to mm b. Convert 6.0 × 10 6 mg to g c. Convert 9.86 × 10 15 m to km d. Convert 1.91 × 10 − 4 kg to mg e. Convert 5.0 ng to mg
Do the following metric system conversions by changing only the power of
10
. For example, convert
2.5
L
to
mL
:
2.5
L
=
2.5
×
10
3
mL
a. Convert
4.5
km
to
mm
b. Convert
6.0
×
10
6
mg
to
g
c. Convert
9.86
×
10
15
m
to
km
d. Convert
1.91
×
10
−
4
kg
to
mg
e. Convert
5.0
ng
to
mg
Expert Solution
Interpretation Introduction
(a)
Interpretation:
The metric system conversion of the given quantity by changing only the power of 10 is to be stated.
Concept introduction:
In metric system of units, the bigger and the smaller units of any quantity are in relation with each other by the factor of 10. It is the most useful unit system. It is a decimal system of units. For example, if the unit of length is 1kilometer then it is equal to 1000meters, according to the metric units.
Answer to Problem 1.100E
The metric system conversion of the given quantity by changing only the power of 10 is 4.5×106mm.
Explanation of Solution
The given quantity is 4.5km. The conversion of km into mm is done as,
1km=1×106mm
Thus, the quantity, 4.5km can be converted into mm as,
4.5km=4.5×106mm
Therefore, the metric system conversion of the given quantity by changing only the power of 10 is 4.5×106mm.
Conclusion
The metric system conversion of the given quantity by changing only the power of 10 is 4.5×106mm.
Expert Solution
Interpretation Introduction
(b)
Interpretation:
The metric system conversion of the given quantity by changing only the power of 10 is to be stated.
Concept introduction:
In metric system of units, the bigger and the smaller units of any quantity are in relation with each other by the factor of 10. It is the most useful unit system. It is a decimal system of units. For example, if the unit of length is 1kilometer then it is equal to 1000meters, according to the metric units.
Answer to Problem 1.100E
The metric system conversion of the given quantity by changing only the power of 10 is 6.0×103g.
Explanation of Solution
The given quantity is 6.0×106mg. The conversion of mg into g is done as,
1mg=1×10−3g
Thus, the quantity, 6.0×106mg can be converted into g as,
6.0×106mg=6.0×106×10−3g=6.0×103g
Therefore, the metric system conversion of the given quantity by changing only the power of 10 is 6.0×103g.
Conclusion
The metric system conversion of the given quantity by changing only the power of 10 is 6.0×103g.
Expert Solution
Interpretation Introduction
(c)
Interpretation:
The metric system conversion of the given quantity by changing only the power of 10 is to be stated.
Concept introduction:
In metric system of units, the bigger and the smaller units of any quantity are in relation with each other by the factor of 10. It is the most useful unit system. It is a decimal system of units. For example, if the unit of length is 1kilometer then it is equal to 1000meters, according to the metric units.
Answer to Problem 1.100E
The metric system conversion of the given quantity by changing only the power of 10 is 9.86×1012km.
Explanation of Solution
The given quantity is 9.86×1015m. The conversion of m into km is done as,
1m=1×10−3km
Thus, the quantity, 9.86×1015m can be converted into km as,
9.86×1015m=9.86×1015×10−3km=9.86×1012km
Therefore, the metric system conversion of the given quantity by changing only the power of 10 is 9.86×1012km.
Conclusion
The metric system conversion of the given quantity by changing only the power of 10 is 9.86×1012km.
Expert Solution
Interpretation Introduction
(d)
Interpretation:
The metric system conversion of the given quantity by changing only the power of 10 is to be stated.
Concept introduction:
In metric system of units, the bigger and the smaller units of any quantity are in relation with each other by the factor of 10. It is the most useful unit system. It is a decimal system of units. For example, if the unit of length is 1kilometer then it is equal to 1000meters, according to the metric units.
Answer to Problem 1.100E
The metric system conversion of the given quantity by changing only the power of 10 is 1.91×102mg.
Explanation of Solution
The given quantity is 1.91×10−4kg. The conversion of kg into mg is done as,
1kg=1×106mg
Thus, the quantity, 1.91×10−4kg can be converted into mg as,
1.91×10−4kg=1.91×10−4×106mg=1.91×102mg
Therefore, the metric system conversion of the given quantity by changing only the power of 10 is 1.91×102mg.
Conclusion
The metric system conversion of the given quantity by changing only the power of 10 is 1.91×102mg.
Expert Solution
Interpretation Introduction
(e)
Interpretation:
The metric system conversion of the given quantity by changing only the power of 10 is to be stated.
Concept introduction:
In metric system of units, the bigger and the smaller units of any quantity are in relation with each other by the factor of 10. It is the most useful unit system. It is a decimal system of units. For example, if the unit of length is 1kilometer then it is equal to 1000meters, according to the metric units.
Answer to Problem 1.100E
The metric system conversion of the given quantity by changing only the power of 10 is 5.0×10−6mg.
Explanation of Solution
The given quantity is 5.0ng. The conversion of ng into mg is done as,
1ng=1×10−6mg
Thus, the quantity, 5.0ng can be converted into mg as,
5.0ng=5.0×10−6mg
Therefore, the metric system conversion of the given quantity by changing only the power of 10 is 5.0×10−6mg.
Conclusion
The metric system conversion of the given quantity by changing only the power of 10 is 5.0×10−6mg.
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(f) SO:
Best Lewis Structure
3
e group geometry:_
shape/molecular geometry:,
(g) CF2CF2
Best Lewis Structure
polarity:
e group arrangement:_
shape/molecular geometry:
(h) (NH4)2SO4
Best Lewis Structure
polarity:
e group arrangement:
shape/molecular geometry:
polarity:
Sketch (with angles):
Sketch (with angles):
Sketch (with angles):
1.
Problem Set 3b
Chem 141
For each of the following compounds draw the BEST Lewis Structure then sketch the molecule (showing
bond angles). Identify (i) electron group geometry (ii) shape around EACH central atom (iii) whether the
molecule is polar or non-polar (iv)
(a) SeF4
Best Lewis Structure
e group arrangement:_
shape/molecular geometry:
polarity:
(b) AsOBr3
Best Lewis Structure
e group arrangement:_
shape/molecular geometry:
polarity:
Sketch (with angles):
Sketch (with angles):
(c) SOCI
Best Lewis Structure
2
e group arrangement:
shape/molecular geometry:_
(d) PCls
Best Lewis Structure
polarity:
e group geometry:_
shape/molecular geometry:_
(e) Ba(BrO2):
Best Lewis Structure
polarity:
e group arrangement:
shape/molecular geometry:
polarity:
Sketch (with angles):
Sketch (with angles):
Sketch (with angles):
Chapter 1 Solutions
Chemistry for Today: General Organic and Biochemistry
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Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell