CONCEPTS OF PROGRAM...(PEARSON CHANNEL)
CONCEPTS OF PROGRAM...(PEARSON CHANNEL)
12th Edition
ISBN: 9780136680758
Author: Sebesta
Publisher: PEARSON
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Chapter 1, Problem 10PS

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Aspects of writing efficient programs with inexpensive hardware:

In present time the cost of hardware has reduced significantly and now a normal person can easily afford personal computers with standard hardware.

  • Even though there has been downfall in the cost of hardware, but there is more effort to produce efficient and quality code.
  • One reason is the execution time. Some programs like system software need to run continuously for long hours.
  • So, they need to be efficient enough to meet the needs of the users. Also some may argue that instead of wasting efforts to optimize code, one can always upgrade his hardware.
  • But who would want to upgrade the hardware for running just one code...

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make corrections of this program based on the errors shown. this is CIS 227 .
Create 6 users: Don, Liz, Shamir, Jose, Kate, and Sal. Create 2 groups: marketing and research. Add Shamir, Jose, and Kate to the marketing group. Add Don, Liz, and Sal to the research group. Create a shared directory for each group. Create two files to put into each directory: spreadsheetJanuary.txt meetingNotes.txt Assign access permissions to the directories:  Groups should have Read+Write access Leave owner permissions as they are  “Everyone else” should not have any access   Submit for grade: Screenshot of  /etc/passwd contents showing your new users Screenshot of /etc/group contents showing new groups with their members Screenshot of shared directories you created with files and permissions
⚫ your circuit diagrams for your basic bricks, such as AND, OR, XOR gates and 1 bit multiplexers, ⚫ your circuit diagrams for your extended full adder, designed in Section 1 and ⚫ your circuit diagrams for your 8-bit arithmetical-logical unit, designed in Section 2. 1 An Extended Full Adder In this Section, we are going to design an extended full adder circuit (EFA). That EFA takes 6 one bit inputs: aj, bj, Cin, Tin, t₁ and to. Depending on the four possible combinations of values on t₁ and to, the EFA produces 3 one bit outputs: sj, Cout and rout. The EFA can be specified in principle by a truth table with 26 = 64 entries and 3 outputs. However, as the EFA ignores certain inputs in certain cases, it is easier to work with the following overview specification, depending only on t₁ and to in the first place: t₁ to Description 00 Output Relationship Ignored Inputs Addition Mode 2 Coutsjaj + bj + Cin, Tout= 0 Tin 0 1 Shift Left Mode Sj = Cin, Cout=bj, rout = 0 rin, aj 10 1 1 Shift Right…

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CONCEPTS OF PROGRAM...(PEARSON CHANNEL)

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