Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1)
Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1)
2nd Edition
ISBN: 9780076602919
Author: McGraw-Hill Education
Publisher: McGraw-Hill Education
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Chapter 0.5, Problem 47E
To determine

The number of 9-inch ribbons that can be cut from 112 yards of ribbon.

Expert Solution & Answer
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Answer to Problem 47E

6 boards, each 2 feet 8 inches long, can be cut from a board 16 feet long.

Explanation of Solution

Given information:

A ribbon 112 yards long.

Formula used:

Mixed fractions of the form mpq can be converted into improper fractions as,

  mpq=(m×q)+pq

Conversion rule of converting yards into inches which can be mathematically expressed as,

  1 yard = 36 inches

Division in real numbers is multiplication by reciprocal. If b0 , then,

  a÷b=a(1b)=ab

Here, 1b is the multiplicative inverse.

Calculation:

Consider the given statement a ribbon 112 yards long.

Recall that mixed fractions of the form mpq can be converted into improper fractions as,

  mpq=(m×q)+pq

So, 112 will be converted as,

  112=( 1×2)+12=32

Recall conversion rule of converting yards into inches which can be mathematically expressed as,

  1 yard = 36 inches

So, 32 yards will be evaluated as when 32 is multiplied by 36 .

  1 yard = 36 inches32yards =3236 inches=54 inches

Now, number of 9-inch ribbons that can be cut from 112 yards of ribbon, will be evaluated when 54 is divided by 9 .

Recall that the division in real numbers is multiplication by reciprocal. If b0 , then,

  a÷b=a(1b)=ab

Here, 1b is the multiplicative inverse.

Sonumber of 9-inch ribbons that can be cut from 112 yards of ribbon, is calculated as,

  54÷9=5419=969=6

Thus, number of 9-inch ribbons that can be cut from 112 yards of ribbon is 6.

Chapter 0 Solutions

Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1)

Ch. 0.2 - Prob. 5ECh. 0.2 - Prob. 6ECh. 0.2 - Prob. 7ECh. 0.2 - Prob. 8ECh. 0.2 - Prob. 9ECh. 0.2 - Prob. 10ECh. 0.2 - Prob. 11ECh. 0.2 - Prob. 12ECh. 0.2 - Prob. 13ECh. 0.2 - Prob. 14ECh. 0.2 - Prob. 15ECh. 0.2 - Prob. 16ECh. 0.2 - Prob. 17ECh. 0.2 - Prob. 18ECh. 0.2 - Prob. 19ECh. 0.2 - Prob. 20ECh. 0.2 - Prob. 21ECh. 0.2 - Prob. 22ECh. 0.2 - Prob. 23ECh. 0.2 - Prob. 24ECh. 0.2 - Prob. 25ECh. 0.2 - Prob. 26ECh. 0.2 - Prob. 27ECh. 0.2 - Prob. 28ECh. 0.2 - Prob. 29ECh. 0.2 - Prob. 30ECh. 0.2 - Prob. 31ECh. 0.2 - Prob. 32ECh. 0.2 - Prob. 33ECh. 0.2 - Prob. 34ECh. 0.2 - Prob. 35ECh. 0.3 - Prob. 1ECh. 0.3 - Prob. 2ECh. 0.3 - Prob. 3ECh. 0.3 - Prob. 4ECh. 0.3 - Prob. 5ECh. 0.3 - Prob. 6ECh. 0.3 - Prob. 7ECh. 0.3 - Prob. 8ECh. 0.3 - Prob. 9ECh. 0.3 - Prob. 10ECh. 0.3 - Prob. 11ECh. 0.3 - Prob. 12ECh. 0.3 - Prob. 13ECh. 0.3 - Prob. 14ECh. 0.3 - Prob. 15ECh. 0.3 - Prob. 16ECh. 0.3 - Prob. 17ECh. 0.3 - Prob. 18ECh. 0.3 - Prob. 19ECh. 0.3 - Prob. 20ECh. 0.3 - Prob. 21ECh. 0.3 - Prob. 22ECh. 0.3 - 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