Chapter 0.10, Problem 9E

To determine

The surface area of cuboid.

Answer to Problem 9E

The surface area of cuboid is ${\text{A=216in}}^{\text{2}}$ .

Explanation of Solution

Given :

l = 12 in

w = 2 in

h = 6 in

Calculation: Surface area:

  $\begin{array}{l}\text{A=2}\left[\text{wl+hl+hw}\right]\\ \text{here,}\\ \text{A=Surface}\text{area}\\ \text{h}\text{=}\text{height}\\ \text{w=}\text{width}\\ \text{l=}\text{length}\end{array}$

So,

Surface area:

  $\begin{array}{l}\text{A=2}\left[\text{wl+hl+hw}\right]\\ \text{A=2}\left[\text{24+72+12}\right]\\ \text{A=2}\left[\text{108}\right]\\ {\text{A=216in}}^{\text{2}}\end{array}$

Therefore, surface area given solid is ${\text{A=216in}}^{\text{2}}$ .