Chapter 0, Problem 42PR

To determine

The area and parameter of the given figure.

Answer to Problem 42PR

  $\begin{array}{l}A=81{\text{ inch}}^2\\ P=36\text{ inch}\end{array}$

Explanation of Solution

Given:

Height of side $a=9$ inch

Formula used:

Area of square

  $A=base\times height$

Parameter of square

  $P=4\times side$

Calculation:

Area of square

  $A=base\times height$

For square the length of base and height is same.

  $\begin{array}{l}A=a\times a\\ A=9\times 9\\ A=81{\text{ inch}}^2\end{array}$

Parameter of square

  $\begin{array}{l}P=4\times side\\ P=4\times a\\ P=4\times 9\\ P=36\text{ inch}\end{array}$

Conclusion:

Hence, the area of square is $81{\text{ inch}}^2$ and parameter of square is $\text{36 inch}$ .