Finite Mathematics
7th Edition
ISBN: 9781337280426
Author: Stefan Waner, Steven Costenoble
Publisher: Cengage Learning
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Chapter 0.2, Problem 55E
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To calculate: The value of expression
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Suppose the number of people who register to attend the Tucson Festival of Books can be modeled by P(t) = k(1.1),
where t is the number of days since the registration window opened. Assume k is a positive constant.
Which of the following represents how long it will take in days for the number of people who register to double?
t =
In(1.1)
In(2)
In(2)
t =
In(1.1)
In(1.1)
t =
t =
t =
In(2) - In(k)
In(2)
In(k) + In(1.1)
In(2) - In(k)
In(1.1)
For unemployed persons in the United States, the average number of months of unemployment at the end of December 2009 was approximately seven months (Bureau of Labor Statistics, January 2010). Suppose the following data are for a particular region in upstate New York. The values in the first column show the number of
months unemployed and the values in the second column show the corresponding number of unemployed persons.
Months
Unemployed
Number
Unemployed
1
1029
2
1686
3
2269
4
2675
5
3487
6
4652
7
4145
8
3587
9
2325
10
1120
Let x be a random variable indicating the number of months a person is unemployed.
a. Use the data to develop an empirical discrete probability distribution for x (to 4 decimals).
(x)
f(x)
1
2
3
4
5
6
7
8
9
10
b. Show that your probability distribution satisfies the conditions for a valid discrete probability distribution.
The input in the box below will not be graded, but may be reviewed and considered by your instructor.
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c. What is the probability that a…
Chapter 0 Solutions
Finite Mathematics
Ch. 0.1 - Prob. 1ECh. 0.1 - Prob. 2ECh. 0.1 - Prob. 3ECh. 0.1 - Prob. 4ECh. 0.1 - Prob. 5ECh. 0.1 - Prob. 6ECh. 0.1 - Prob. 7ECh. 0.1 - Prob. 8ECh. 0.1 - Prob. 9ECh. 0.1 - Prob. 10E
Ch. 0.1 - Prob. 11ECh. 0.1 - Prob. 12ECh. 0.1 - Prob. 13ECh. 0.1 - Calculate each expression in Exercises 124, giving...Ch. 0.1 - Prob. 15ECh. 0.1 - Prob. 16ECh. 0.1 - Calculate each expression in Exercises 124, giving...Ch. 0.1 - Calculate each expression in Exercises 124, giving...Ch. 0.1 - Prob. 19ECh. 0.1 - Prob. 20ECh. 0.1 - Prob. 21ECh. 0.1 - Prob. 22ECh. 0.1 - Prob. 23ECh. 0.1 - Calculate each expression in Exercises 124, giving...Ch. 0.1 - Prob. 25ECh. 0.1 - Prob. 26ECh. 0.1 - Prob. 27ECh. 0.1 - Prob. 28ECh. 0.1 - Prob. 29ECh. 0.1 - Prob. 30ECh. 0.1 - Prob. 31ECh. 0.1 - Prob. 32ECh. 0.1 - Prob. 33ECh. 0.1 - Prob. 34ECh. 0.1 - Convert each expression in Exercises 25-50 into...Ch. 0.1 - Convert each expression in Exercises 25-50 into...Ch. 0.1 - Convert each expression in Exercises 25-50 into...Ch. 0.1 - Prob. 38ECh. 0.1 - Prob. 39ECh. 0.1 - Prob. 40ECh. 0.1 - Prob. 41ECh. 0.1 - Prob. 42ECh. 0.1 - Prob. 43ECh. 0.1 - Prob. 44ECh. 0.1 - Prob. 45ECh. 0.1 - Prob. 46ECh. 0.1 - Prob. 47ECh. 0.1 - Prob. 48ECh. 0.1 - Prob. 49ECh. 0.1 - Prob. 50ECh. 0.2 - Prob. 1ECh. 0.2 - Prob. 2ECh. 0.2 - Prob. 3ECh. 0.2 - Prob. 4ECh. 0.2 - Prob. 5ECh. 0.2 - Prob. 6ECh. 0.2 - Prob. 7ECh. 0.2 - Prob. 8ECh. 0.2 - Prob. 9ECh. 0.2 - Prob. 10ECh. 0.2 - Prob. 11ECh. 0.2 - Prob. 12ECh. 0.2 - Prob. 13ECh. 0.2 - Prob. 14ECh. 0.2 - Prob. 15ECh. 0.2 - Prob. 16ECh. 0.2 - Prob. 17ECh. 0.2 - Prob. 18ECh. 0.2 - Prob. 19ECh. 0.2 - Prob. 20ECh. 0.2 - Prob. 21ECh. 0.2 - Prob. 22ECh. 0.2 - Prob. 23ECh. 0.2 - Prob. 24ECh. 0.2 - Prob. 25ECh. 0.2 - Prob. 26ECh. 0.2 - Prob. 27ECh. 0.2 - Prob. 28ECh. 0.2 - Prob. 29ECh. 0.2 - Prob. 30ECh. 0.2 - Prob. 31ECh. 0.2 - Prob. 32ECh. 0.2 - Prob. 33ECh. 0.2 - Prob. 34ECh. 0.2 - Convert the expressions in Exercises 31-36 to...Ch. 0.2 - Prob. 36ECh. 0.2 - Prob. 37ECh. 0.2 - Prob. 38ECh. 0.2 - Prob. 39ECh. 0.2 - Prob. 40ECh. 0.2 - Prob. 41ECh. 0.2 - Prob. 42ECh. 0.2 - Prob. 43ECh. 0.2 - Prob. 44ECh. 0.2 - Prob. 45ECh. 0.2 - Prob. 46ECh. 0.2 - Prob. 47ECh. 0.2 - Evaluate expressions in Exercises 3756, rounding...Ch. 0.2 - Prob. 49ECh. 0.2 - Prob. 50ECh. 0.2 - Prob. 51ECh. 0.2 - Prob. 52ECh. 0.2 - Prob. 53ECh. 0.2 - Prob. 54ECh. 0.2 - Prob. 55ECh. 0.2 - Prob. 56ECh. 0.2 - Prob. 57ECh. 0.2 - Prob. 58ECh. 0.2 - Prob. 59ECh. 0.2 - Prob. 60ECh. 0.2 - Prob. 61ECh. 0.2 - Prob. 62ECh. 0.2 - Prob. 63ECh. 0.2 - Prob. 64ECh. 0.2 - Prob. 65ECh. 0.2 - Prob. 66ECh. 0.2 - Prob. 67ECh. 0.2 - Prob. 68ECh. 0.2 - Prob. 69ECh. 0.2 - Prob. 70ECh. 0.2 - Prob. 71ECh. 0.2 - Prob. 72ECh. 0.2 - Prob. 73ECh. 0.2 - Prob. 74ECh. 0.2 - Prob. 75ECh. 0.2 - Prob. 76ECh. 0.2 - Prob. 77ECh. 0.2 - Prob. 78ECh. 0.2 - Prob. 79ECh. 0.2 - Prob. 80ECh. 0.2 - Prob. 81ECh. 0.2 - Prob. 82ECh. 0.2 - Prob. 83ECh. 0.2 - Prob. 84ECh. 0.2 - Prob. 85ECh. 0.2 - Prob. 86ECh. 0.2 - Prob. 87ECh. 0.2 - Prob. 88ECh. 0.2 - Prob. 89ECh. 0.2 - Prob. 90ECh. 0.2 - Prob. 91ECh. 0.2 - Prob. 92ECh. 0.2 - Prob. 93ECh. 0.2 - Prob. 94ECh. 0.2 - Prob. 95ECh. 0.2 - Prob. 96ECh. 0.2 - Prob. 97ECh. 0.2 - Prob. 98ECh. 0.2 - Prob. 99ECh. 0.2 - Prob. 100ECh. 0.2 - Prob. 101ECh. 0.2 - Prob. 102ECh. 0.2 - Prob. 103ECh. 0.2 - Prob. 104ECh. 0.2 - Prob. 105ECh. 0.2 - Prob. 106ECh. 0.2 - Prob. 107ECh. 0.2 - Prob. 108ECh. 0.2 - Prob. 109ECh. 0.2 - Prob. 110ECh. 0.2 - Prob. 111ECh. 0.2 - Prob. 112ECh. 0.2 - Prob. 113ECh. 0.2 - Prob. 114ECh. 0.2 - Prob. 115ECh. 0.2 - Prob. 116ECh. 0.2 - Prob. 117ECh. 0.2 - Prob. 118ECh. 0.2 - Prob. 119ECh. 0.2 - Prob. 120ECh. 0.3 - Expand each expression in Exercises 122. x(4x+6)Ch. 0.3 - Prob. 2ECh. 0.3 - Prob. 3ECh. 0.3 - Prob. 4ECh. 0.3 - Prob. 5ECh. 0.3 - Prob. 6ECh. 0.3 - Prob. 7ECh. 0.3 - Prob. 8ECh. 0.3 - Prob. 9ECh. 0.3 - Prob. 10ECh. 0.3 - Prob. 11ECh. 0.3 - Prob. 12ECh. 0.3 - Prob. 13ECh. 0.3 - Prob. 14ECh. 0.3 - Prob. 15ECh. 0.3 - Prob. 16ECh. 0.3 - Expand each expression in Exercises 122....Ch. 0.3 - Prob. 18ECh. 0.3 - Prob. 19ECh. 0.3 - Prob. 20ECh. 0.3 - Prob. 21ECh. 0.3 - Prob. 22ECh. 0.3 - Prob. 23ECh. 0.3 - Prob. 24ECh. 0.3 - In Exercises 2330, factor each expression and...Ch. 0.3 - Prob. 26ECh. 0.3 - Prob. 27ECh. 0.3 - Prob. 28ECh. 0.3 - Prob. 29ECh. 0.3 - In Exercises 2330, factor each expression and...Ch. 0.3 - Prob. 31ECh. 0.3 - Prob. 32ECh. 0.3 - Prob. 33ECh. 0.3 - Prob. 34ECh. 0.3 - Prob. 35ECh. 0.3 - In Exercises 3148, (a) factor the given...Ch. 0.3 - Prob. 37ECh. 0.3 - Prob. 38ECh. 0.3 - Prob. 39ECh. 0.3 - In Exercises 3148, (a) factor the given...Ch. 0.3 - Prob. 41ECh. 0.3 - Prob. 42ECh. 0.3 - Prob. 43ECh. 0.3 - Prob. 44ECh. 0.3 - Prob. 45ECh. 0.3 - Prob. 46ECh. 0.3 - Prob. 47ECh. 0.3 - Prob. 48ECh. 0.4 - Prob. 1ECh. 0.4 - Prob. 2ECh. 0.4 - Prob. 3ECh. 0.4 - Prob. 4ECh. 0.4 - Prob. 5ECh. 0.4 - Prob. 6ECh. 0.4 - Prob. 7ECh. 0.4 - Prob. 8ECh. 0.4 - Prob. 9ECh. 0.4 - Prob. 10ECh. 0.4 - Prob. 11ECh. 0.4 - Rewrite each expression in Exercises 116 as a...Ch. 0.4 - Prob. 13ECh. 0.4 - Prob. 14ECh. 0.4 - Prob. 15ECh. 0.4 - Prob. 16ECh. 0.5 - Solve the equations in Exercises 112 for x...Ch. 0.5 - Prob. 2ECh. 0.5 - Prob. 3ECh. 0.5 - Prob. 4ECh. 0.5 - Prob. 5ECh. 0.5 - Prob. 6ECh. 0.5 - Prob. 7ECh. 0.5 - Prob. 8ECh. 0.5 - Prob. 9ECh. 0.5 - Prob. 10ECh. 0.5 - Prob. 11ECh. 0.5 - Solve the equations in Exercises 112 for x...Ch. 0.5 - Prob. 13ECh. 0.5 - Prob. 14ECh. 0.5 - Prob. 15ECh. 0.5 - Prob. 16ECh. 0.5 - Prob. 17ECh. 0.5 - Prob. 18ECh. 0.5 - Prob. 19ECh. 0.5 - Prob. 20ECh. 0.5 - Prob. 21ECh. 0.5 - Prob. 22ECh. 0.5 - Prob. 23ECh. 0.5 - Prob. 24ECh. 0.5 - Prob. 25ECh. 0.5 - Prob. 26ECh. 0.5 - Prob. 27ECh. 0.5 - Prob. 28ECh. 0.5 - Prob. 29ECh. 0.5 - Prob. 30ECh. 0.5 - Prob. 31ECh. 0.5 - Prob. 32ECh. 0.5 - Prob. 33ECh. 0.5 - Prob. 34ECh. 0.5 - Prob. 35ECh. 0.5 - Prob. 36ECh. 0.5 - Find all possible real solutions of each equation...Ch. 0.5 - Prob. 38ECh. 0.5 - Prob. 39ECh. 0.5 - Find all possible real solutions of each equation...Ch. 0.5 - Prob. 41ECh. 0.5 - Prob. 42ECh. 0.5 - Prob. 43ECh. 0.5 - Prob. 44ECh. 0.6 - Prob. 1ECh. 0.6 - Prob. 2ECh. 0.6 - Prob. 3ECh. 0.6 - Prob. 4ECh. 0.6 - Prob. 5ECh. 0.6 - Prob. 6ECh. 0.6 - Prob. 7ECh. 0.6 - Prob. 8ECh. 0.6 - Prob. 9ECh. 0.6 - Prob. 10ECh. 0.6 - Solve the equations in Exercises 126....Ch. 0.6 - Prob. 12ECh. 0.6 - Prob. 13ECh. 0.6 - Prob. 14ECh. 0.6 - Prob. 15ECh. 0.6 - Prob. 16ECh. 0.6 - Prob. 17ECh. 0.6 - Prob. 18ECh. 0.6 - Prob. 19ECh. 0.6 - Prob. 20ECh. 0.6 - Prob. 21ECh. 0.6 - Prob. 22ECh. 0.6 - Prob. 23ECh. 0.6 - Prob. 24ECh. 0.6 - Prob. 25ECh. 0.6 - Prob. 26ECh. 0.7 - Referring to the following figure, determine the...Ch. 0.7 - Prob. 2ECh. 0.7 - Prob. 3ECh. 0.7 - Prob. 4ECh. 0.7 - Prob. 5ECh. 0.7 - Prob. 6ECh. 0.7 - Prob. 7ECh. 0.7 - Prob. 8ECh. 0.7 - Prob. 9ECh. 0.7 - Prob. 10ECh. 0.7 - Prob. 11ECh. 0.7 - Prob. 12ECh. 0.7 - Prob. 13ECh. 0.7 - Prob. 14ECh. 0.7 - Prob. 15ECh. 0.7 - Prob. 16ECh. 0.7 - Prob. 17ECh. 0.7 - Find the value of k such that (k,k) is equidistant...Ch. 0.7 - Describe the set of points (x,y) such that...Ch. 0.7 - Prob. 20ECh. 0.8 - In Exercises 14, complete the given tables....Ch. 0.8 - In Exercises 14, complete the given tables....Ch. 0.8 - In Exercises 14, complete the given tables....Ch. 0.8 - In Exercises 14, complete the given tables....Ch. 0.8 - In Exercises 516, evaluate the given quantity....Ch. 0.8 - In Exercises 516, evaluate the given quantity....Ch. 0.8 - In Exercises 516, evaluate the given quantity....Ch. 0.8 - In Exercises 516, evaluate the given quantity....Ch. 0.8 - In Exercises 516, evaluate the given quantity....Ch. 0.8 - In Exercises 516, evaluate the given quantity....Ch. 0.8 - In Exercises 516, evaluate the given quantity....Ch. 0.8 - In Exercises 516, evaluate the given quantity....Ch. 0.8 - In Exercises 516, evaluate the given quantity....Ch. 0.8 - Prob. 14ECh. 0.8 - Prob. 15ECh. 0.8 - In Exercises 516, evaluate the given quantity....Ch. 0.8 - In Exercises 1728, use the logarithm identities to...Ch. 0.8 - In Exercises 1728, use the logarithm identities to...Ch. 0.8 - In Exercises 1728, use the logarithm identities to...Ch. 0.8 - In Exercises 1728, use the logarithm identities to...Ch. 0.8 - In Exercises 1728, use the logarithm identities to...Ch. 0.8 - In Exercises 1728, use the logarithm identities to...Ch. 0.8 - Prob. 23ECh. 0.8 - Prob. 24ECh. 0.8 - Prob. 25ECh. 0.8 - Prob. 26ECh. 0.8 - Prob. 27ECh. 0.8 - Prob. 28ECh. 0.8 - Let a=log2,b=log3, and c=log7. In Exercises 2946,...Ch. 0.8 - Prob. 30ECh. 0.8 - Prob. 31ECh. 0.8 - Prob. 32ECh. 0.8 - Let a=log2,b=log3, and c=log7. In Exercises 2946,...Ch. 0.8 - Prob. 34ECh. 0.8 - Prob. 35ECh. 0.8 - Prob. 36ECh. 0.8 - Prob. 37ECh. 0.8 - Prob. 38ECh. 0.8 - Prob. 39ECh. 0.8 - Let a=log2,b=log3, and c=log7. In Exercises 2946,...Ch. 0.8 - Let a=log2,b=log3, and c=log7. In Exercises 2946,...Ch. 0.8 - Let a=log2,b=log3, and c=log7. In Exercises 2946,...Ch. 0.8 - Let a=log2,b=log3, and c=log7. In Exercises 2946,...Ch. 0.8 - Let a=log2,b=log3, and c=log7. In Exercises 2946,...Ch. 0.8 - Let a=log2,b=log3, and c=log7. In Exercises 2946,...Ch. 0.8 - Let a=log2,b=log3, and c=log7. In Exercises 2946,...Ch. 0.8 - In Exercises 4756, solve the given equation for...Ch. 0.8 - In Exercises 4756, solve the given equation for...Ch. 0.8 - In Exercises 4756, solve the given equation for...Ch. 0.8 - In Exercises 4756, solve the given equation for...Ch. 0.8 - In Exercises 4756, solve the given equation for...Ch. 0.8 - In Exercises 4756, solve the given equation for...Ch. 0.8 - In Exercises 4756, solve the given equation for...Ch. 0.8 - In Exercises 4756, solve the given equation for...Ch. 0.8 - In Exercises 4756, solve the given equation for...Ch. 0.8 - In Exercises 4756, solve the given equation for...
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- West Virginia has one of the highest divorce rates in the nation, with an annual rate of approximately 5 divorces per 1000 people (Centers for Disease Control and Prevention website, January 12, 2012). The Marital Counseling Center, Inc. (MCC) thinks that the high divorce rate in the state may require them to hire additional staff. Working with a consultant, the management of MCC has developed the following probability distribution for x = the number of new clients for marriage counseling for the next year. Excel File: data05-19.xls x 10 f(x) .05 20 30 .10 .10 40 .20 50 60 .35 .20 a. Is this probability distribution valid? - Select your answer- Explain. f(x) Σf(x) Select your answer Select your answer b. What is the probability MCC will obtain more than 30 new clients (to 2 decimals)? c. What is the probability MCC will obtain fewer than 20 new clients (to 2 decimals)? d. Compute the expected value and variance of x. Expected value Variance clients per year squared clients per yeararrow_forwardFor unemployed persons in the United States, the average number of months of unemployment at the end of December 2009 was approximately seven months (Bureau of Labor Statistics, January 2010). Suppose the following data are for a particular region in upstate New York. The values in the first column show the number of months unemployed and the values in the second column show the corresponding number of unemployed persons. Months Unemployed Number Unemployed 1 1029 2 1686 3 2269 4 2675 5 3487 6 4652 7 4145 8 3587 9 2325 10 1120 Let x be a random variable indicating the number of months a person is unemployed. a. Use the data to develop an empirical discrete probability distribution for x (to 4 decimals). (x) f(x) 1 2 3 4 5 6 7 8 9 10 b. Show that your probability distribution satisfies the conditions for a valid discrete probability distribution. The input in the box below will not be graded, but may be reviewed and considered by your instructor. c. What is the probability that a person…arrow_forwardIn Gallup's Annual Consumption Habits Poll, telephone interviews were conducted for a random sample of 1014 adults aged 18 and over. One of the questions was "How many cups of coffee, if any, do you drink on an average day?" The following table shows the results obtained (Gallup website, August 6, 2012). Excel File: data05-23.xls Number of Cups per Day Number of Responses 0 365 264 193 3 4 or more 91 101 Define a random variable x = number of cups of coffee consumed on an average day. Let x = 4 represent four or more cups. Round your answers to four decimal places. a. Develop a probability distribution for x. x 0 1 2 3 4 f(x) b. Compute the expected value of x. cups of coffee c. Compute the variance of x. cups of coffee squared d. Suppose we are only interested in adults that drink at least one cup of coffee on an average day. For this group, let y = the number of cups of coffee consumed on an average day. Compute the expected value of y. Compare it to the expected value of x. The…arrow_forward
- rounded to two decimal places at each calculationarrow_forwardIn Gallup's Annual Consumption Habits Poll, telephone interviews were conducted for a random sample of 1014 adults aged 18 and over. One of the questions was "How many cups of coffee, if any, do you drink on an average day?" The following table shows the results obtained (Gallup website, August 6, 2012). Excel File: data05-23.xls Number of Cups per Day Number of Responses 0 365 264 193 2 3 4 or more 91 101 Define a random variable x = number of cups of coffee consumed on an average day. Let x = 4 represent four or more cups. Round your answers to four decimal places. a. Develop a probability distribution for x. x 0 1 2 3 f(x) b. Compute the expected value of x. cups of coffee c. Compute the variance of x. cups of coffee squared d. Suppose we are only interested in adults that drink at least one cup of coffee on an average day. For this group, let y = the number of cups of coffee consumed on an average day. Compute the expected value of y. Compare it to the expected value of x. The…arrow_forwardA technician services mailing machines at companies in the Phoenix area. Depending on the type of malfunction, the service call can take 1, 2, 3, or 4 hours. The different types of malfunctions occur at about the same frequency. Develop a probability distribution for the duration of a service call. Duration of Call x f(x) 1 2 3 4 Which of the following probability distribution graphs accurately represents the data set? Consider the required conditions for a discrete probability function, shown below.Does this probability distribution satisfy equation (5.1)?Does this probability distribution satisfy equation (5.2)? What is the probability a service call will take three hours? A service call has just come in, but the type of malfunction is unknown. It is 3:00 P.M. and service technicians usually get off at 5:00 P.M. What is the probability the service technician will have to work overtime to fix the machine today?arrow_forward
- A psychologist determined that the number of sessions required to obtain the trust of a new patient is either 1, 2, or 3. Let x be a random variable indicating the number of sessions required to gain the patient's trust. The following probability function has been proposed. x f(x) for x = 1, 2, or 3 a. Consider the required conditions for a discrete probability function, shown below. f(x) ≥0 Σf(x) = 1 (5.1) (5.2) Does this probability distribution satisfy equation (5.1)? Select Does this probability distribution satisfy equation (5.2)? Select b. What is the probability that it takes exactly 2 sessions to gain the patient's trust (to 3 decimals)? c. What is the probability that it takes at least 2 sessions to gain the patient's trust (to 3 decimals)?arrow_forwardA technician services mailing machines at companies in the Phoenix area. Depending on the type of malfunction, the service call can take 1, 2, 3, or 4 hours. The different types of malfunctions occur at about the same frequency. Develop a probability distribution for the duration of a service call. Which of the following probability distribution graphs accurately represents the data set? Consider the required conditions for a discrete probability function, shown below.Does this probability distribution satisfy equation (5.1)?Does this probability distribution satisfy equation (5.2)? What is the probability a service call will take three hours? A service call has just come in, but the type of malfunction is unknown. It is 3:00 P.M. and service technicians usually get off at 5:00 P.M. What is the probability the service technician will have to work overtime to fix the machine today?arrow_forwardWest Virginia has one of the highest divorce rates in the nation, with an annual rate of approximately 5 divorces per 1000 people (Centers for Disease Control and Prevention website, January 12, 2012). The Marital Counseling Center, Inc. (MCC) thinks that the high divorce rate in the state may require them to hire additional staff. Working with a consultant, the management of MCC has developed the following probability distribution for x = the number of new clients for marriage counseling for the next year. Excel File: data05-19.xls 10 20 f(x) .05 .10 11 30 40 50 60 .10 .20 .35 .20 a. Is this probability distribution valid? Yes Explain. greater than or equal to 0 f(x) Σf(x) equal to 1 b. What is the probability MCC will obtain more than 30 new clients (to 2 decimals)? c. What is the probability MCC will obtain fewer than 20 new clients (to 2 decimals)? d. Compute the expected value and variance of x. Expected value Variance clients per year squared clients per yeararrow_forward
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