Pre-Algebra, Student Edition
Pre-Algebra, Student Edition
1st Edition
ISBN: 9780078885150
Author: McGraw-Hill
Publisher: Glencoe/McGraw-Hill
bartleby

Concept explainers

Continuous Probability Distributions
Probability distributions are of two types, which are continuous probability distributions and discrete probability distributions. A continuous probability distribution contains an infinite number of values. For example, if time is infinite: you could co…
Normal Distribution
Suppose we had to design a bathroom weighing scale, how would we decide what should be the range of the weighing machine? Would we take the highest recorded human weight in history and use that as the upper limit for our weighing scale? This may not be a…
bartleby

Videos

Question
Book Icon
Chapter 0, Problem 51P
To determine

To complete: the given blank.

Expert Solution & Answer
Check Mark

Answer to Problem 51P

The result is 1656mm = 165.6cm

Explanation of Solution

Given:

  1656mm=_cm

Calculation:

The given units are customary units of lengths. For conversion, please refer to conversion table given in book, reproduce here.

    Unit 1Unit 2
    1 centimeter (cm)10 millimeter (mm)
    1 meter (m)100 centimeter (cm)
    1 kilometer (km)1000 meter (m)

Since 1 cm = 10mm, to get centimeters in 1656 millimeters, must find how many 10 millimeters are in 1656 millimeters.

Thus, divide 1656 by 10

Hence,

  1656mm=(1656÷10)cmor1656mm=165.6cm

Conclusion:

The result is 1656mm = 165.6cm

Previous
Chapter 0, Problem 50P
Next
Chapter 0, Problem 52P

Chapter 0 Solutions

Pre-Algebra, Student Edition

Ch. 0.1 - Prob. 1ECh. 0.1 - Prob. 2ECh. 0.1 - Prob. 3ECh. 0.1 - Prob. 4ECh. 0.2 - Prob. 1ECh. 0.2 - Prob. 2ECh. 0.2 - Prob. 3ECh. 0.2 - Prob. 4ECh. 0.2 - Prob. 5ECh. 0.2 - Prob. 6E
Ch. 0.2 - Prob. 7ECh. 0.2 - Prob. 8ECh. 0.2 - Prob. 9ECh. 0.2 - Prob. 10ECh. 0.2 - Prob. 11ECh. 0.2 - Prob. 12ECh. 0.2 - Prob. 13ECh. 0.2 - Prob. 14ECh. 0.2 - Prob. 15ECh. 0.2 - Prob. 16ECh. 0.2 - Prob. 17ECh. 0.2 - Prob. 18ECh. 0.2 - Prob. 19ECh. 0.3 - Prob. 1ECh. 0.3 - Prob. 2ECh. 0.3 - Prob. 3ECh. 0.3 - Prob. 4ECh. 0.3 - Prob. 5ECh. 0.3 - Prob. 6ECh. 0.3 - Prob. 7ECh. 0.3 - Prob. 8ECh. 0.3 - Prob. 9ECh. 0.3 - Prob. 10ECh. 0.3 - Prob. 11ECh. 0.3 - Prob. 12ECh. 0.3 - Prob. 13ECh. 0.3 - Prob. 14ECh. 0.3 - Prob. 15ECh. 0.3 - Prob. 16ECh. 0.3 - Prob. 17ECh. 0.3 - Prob. 18ECh. 0.3 - Prob. 19ECh. 0.3 - Prob. 20ECh. 0.3 - Prob. 21ECh. 0.3 - Prob. 22ECh. 0.3 - Prob. 23ECh. 0.3 - Prob. 24ECh. 0.3 - Prob. 25ECh. 0.3 - Prob. 26ECh. 0.4 - Prob. 1ECh. 0.4 - Prob. 2ECh. 0.4 - Prob. 3ECh. 0.4 - Prob. 4ECh. 0.4 - Prob. 5ECh. 0.4 - Prob. 6ECh. 0.4 - Prob. 7ECh. 0.5 - Prob. 1ECh. 0.5 - Prob. 2ECh. 0.5 - Prob. 3ECh. 0.5 - Prob. 4ECh. 0.5 - Prob. 5ECh. 0.5 - Prob. 6ECh. 0.5 - Prob. 7ECh. 0.5 - Prob. 8ECh. 0.5 - Prob. 9ECh. 0.5 - Prob. 10ECh. 0.5 - Prob. 11ECh. 0.5 - Prob. 12ECh. 0.5 - Prob. 13ECh. 0.6 - Prob. 1ECh. 0.6 - Prob. 2ECh. 0.6 - Prob. 3ECh. 0.6 - Prob. 4ECh. 0.6 - Prob. 5ECh. 0.6 - Prob. 6ECh. 0.6 - Prob. 7ECh. 0.6 - Prob. 8ECh. 0.6 - Prob. 9ECh. 0.6 - Prob. 10ECh. 0.6 - Prob. 11ECh. 0.6 - Prob. 12ECh. 0.6 - Prob. 13ECh. 0.6 - Prob. 14ECh. 0.6 - Prob. 15ECh. 0.6 - Prob. 16ECh. 0.6 - Prob. 17ECh. 0.6 - Prob. 18ECh. 0.6 - Prob. 19ECh. 0.6 - Prob. 20ECh. 0.6 - Prob. 21ECh. 0.6 - Prob. 22ECh. 0.7 - Prob. 1ECh. 0.7 - Prob. 2ECh. 0.7 - Prob. 3ECh. 0.7 - Prob. 4ECh. 0.7 - Prob. 5ECh. 0.7 - Prob. 6ECh. 0.7 - Prob. 7ECh. 0.7 - Prob. 8ECh. 0.7 - Prob. 9ECh. 0 - Prob. 1PRCh. 0 - Prob. 2PRCh. 0 - Prob. 3PRCh. 0 - Prob. 4PRCh. 0 - Prob. 5PRCh. 0 - Prob. 6PRCh. 0 - Prob. 7PRCh. 0 - Prob. 8PRCh. 0 - Prob. 9PRCh. 0 - Prob. 10PRCh. 0 - Prob. 11PRCh. 0 - Prob. 12PRCh. 0 - Prob. 13PRCh. 0 - Prob. 14PRCh. 0 - Prob. 15PRCh. 0 - Prob. 16PRCh. 0 - Prob. 17PRCh. 0 - Prob. 18PRCh. 0 - Prob. 19PRCh. 0 - Prob. 20PRCh. 0 - Prob. 21PRCh. 0 - Prob. 22PRCh. 0 - Prob. 23PRCh. 0 - Prob. 24PRCh. 0 - Prob. 25PRCh. 0 - Prob. 26PRCh. 0 - Prob. 27PRCh. 0 - Prob. 28PRCh. 0 - Prob. 29PRCh. 0 - Prob. 30PRCh. 0 - Prob. 31PRCh. 0 - Prob. 32PRCh. 0 - Prob. 33PRCh. 0 - Prob. 34PRCh. 0 - Prob. 35PRCh. 0 - Prob. 36PRCh. 0 - Prob. 37PRCh. 0 - Prob. 38PRCh. 0 - Prob. 39PRCh. 0 - Prob. 40PRCh. 0 - Prob. 41PRCh. 0 - Prob. 42PRCh. 0 - Prob. 43PRCh. 0 - Prob. 44PRCh. 0 - Prob. 45PRCh. 0 - Prob. 46PRCh. 0 - Prob. 47PRCh. 0 - Prob. 48PRCh. 0 - Prob. 49PRCh. 0 - Prob. 50PRCh. 0 - Prob. 51PRCh. 0 - Prob. 52PRCh. 0 - Prob. 53PRCh. 0 - Prob. 1PCh. 0 - Prob. 2PCh. 0 - Prob. 3PCh. 0 - Prob. 4PCh. 0 - Prob. 5PCh. 0 - Prob. 6PCh. 0 - Prob. 7PCh. 0 - Prob. 8PCh. 0 - Prob. 9PCh. 0 - Prob. 10PCh. 0 - Prob. 11PCh. 0 - Prob. 12PCh. 0 - Prob. 13PCh. 0 - Prob. 14PCh. 0 - Prob. 15PCh. 0 - Prob. 16PCh. 0 - Prob. 17PCh. 0 - Prob. 18PCh. 0 - Prob. 19PCh. 0 - Prob. 20PCh. 0 - Prob. 21PCh. 0 - Prob. 22PCh. 0 - Prob. 23PCh. 0 - Prob. 24PCh. 0 - Prob. 25PCh. 0 - Prob. 26PCh. 0 - Prob. 27PCh. 0 - Prob. 28PCh. 0 - Prob. 29PCh. 0 - Prob. 30PCh. 0 - Prob. 31PCh. 0 - Prob. 32PCh. 0 - Prob. 33PCh. 0 - Prob. 34PCh. 0 - Prob. 35PCh. 0 - Prob. 36PCh. 0 - Prob. 37PCh. 0 - Prob. 38PCh. 0 - Prob. 39PCh. 0 - Prob. 40PCh. 0 - Prob. 41PCh. 0 - Prob. 42PCh. 0 - Prob. 43PCh. 0 - Prob. 44PCh. 0 - Prob. 45PCh. 0 - Prob. 46PCh. 0 - Prob. 47PCh. 0 - Prob. 48PCh. 0 - Prob. 49PCh. 0 - Prob. 50PCh. 0 - Prob. 51PCh. 0 - Prob. 52PCh. 0 - Prob. 53PCh. 0 - Prob. 54PCh. 0 - Prob. 55PCh. 0 - Prob. 56PCh. 0 - Prob. 57PCh. 0 - Prob. 58P

Additional Math Textbook Solutions

Find more solutions based on key concepts
Find the volumes of the regions in Exercises 23–36. 27. The tetrahedron in the first octant bounded by the coor...

University Calculus: Early Transcendentals (4th Edition)

log a =

Precalculus

Assessment 1-1A How many triangles are in the following figure?

A Problem Solving Approach To Mathematics For Elementary School Teachers (13th Edition)

Females’ Pulse Rates before and after a Fright (Example 17) In a statistics class taught by one of the authors,...

Introductory Statistics

Two dice are thrown. Let E be the event that the sum of the dice is odd, let F be the event that at least one o...

A First Course in Probability (10th Edition)

CHECK POINT I Let p and q represent the following statements: p : 3 + 5 = 8 q : 2 × 7 = 20. Determine the truth...

Thinking Mathematically (6th Edition)

Knowledge Booster
Background pattern image
Algebra
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, algebra and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Text book image
Algebra and Trigonometry (6th Edition)
Algebra
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:PEARSON
Text book image
Contemporary Abstract Algebra
Algebra
ISBN:9781305657960
Author:Joseph Gallian
Publisher:Cengage Learning
Text book image
Linear Algebra: A Modern Introduction
Algebra
ISBN:9781285463247
Author:David Poole
Publisher:Cengage Learning
Text book image
Algebra And Trigonometry (11th Edition)
Algebra
ISBN:9780135163078
Author:Michael Sullivan
Publisher:PEARSON
Text book image
Introduction to Linear Algebra, Fifth Edition
Algebra
ISBN:9780980232776
Author:Gilbert Strang
Publisher:Wellesley-Cambridge Press
Text book image
College Algebra (Collegiate Math)
Algebra
ISBN:9780077836344
Author:Julie Miller, Donna Gerken
Publisher:McGraw-Hill Education
SEE MORE TEXTBOOKS
Continuous Probability Distributions - Basic Introduction; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=QxqxdQ_g2uw;License: Standard YouTube License, CC-BY
Probability Density Function (p.d.f.) Finding k (Part 1) | ExamSolutions; Author: ExamSolutions;https://www.youtube.com/watch?v=RsuS2ehsTDM;License: Standard YouTube License, CC-BY
Find the value of k so that the Function is a Probability Density Function; Author: The Math Sorcerer;https://www.youtube.com/watch?v=QqoCZWrVnbA;License: Standard Youtube License