Z I 1 1 1 1 X I This sketch is about 1800 pm wide. The coordinate (x, y, and z) axes are also shown. You can rotate the sketch for a better view of the orbital by dragging the slider with your mouse. Suppose an atom with its nucleus at the origin has an electron in a 3d, orbital. Complete each row of the table below by deciding how P₁, the probability finding the electron at point A, compares to PR, the probability of finding the electron at point B. B' point A 200 pm in front of the nucleus, along the -y axis. 200 pm above the nucleus, along the +z axis. 200 pm to the right of the nucleus, along the +x axis. point B 200 behind the nucleus, along the +y axis. 200 pm below the nucleus along the -z axis. 200 pm to the left of the nucleus, along the -x axis. compare PA to PB O PA O PA PB OP PA PB P PB A

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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i
1
Z
I 1 1
X
1
This sketch is about 1800 pm wide.
The coordinate (x, y, and z) axes are also shown.
You can rotate the sketch for a better view of the orbital by dragging the slider with your mouse.
Suppose an atom with its nucleus at the origin has an electron in a 3d, orbital. Complete each row of the table below by deciding how PA the probability c
finding the electron at point A, compares to PB, the probability of finding the electron at point B.
point A
200 pm in front of the nucleus, along the -y axis.
200 pm above the nucleus, along the +z axis.
200 pm to the right of the nucleus, along the +x axis.
point B
200 pm behind the nucleus, along the +y axis.
200 pm below the nucleus along the -z axis.
200 pm to the left of the nucleus, along the -x axis.
compare PA to PB
B
O P <P
OP = P
A
P > P
A
PA <PB
O P = PR
A
B
Р
>
PA PB
P<PB
P₁ = PB
A
O
O
O
B
P > P
A
B
Transcribed Image Text:i 1 Z I 1 1 X 1 This sketch is about 1800 pm wide. The coordinate (x, y, and z) axes are also shown. You can rotate the sketch for a better view of the orbital by dragging the slider with your mouse. Suppose an atom with its nucleus at the origin has an electron in a 3d, orbital. Complete each row of the table below by deciding how PA the probability c finding the electron at point A, compares to PB, the probability of finding the electron at point B. point A 200 pm in front of the nucleus, along the -y axis. 200 pm above the nucleus, along the +z axis. 200 pm to the right of the nucleus, along the +x axis. point B 200 pm behind the nucleus, along the +y axis. 200 pm below the nucleus along the -z axis. 200 pm to the left of the nucleus, along the -x axis. compare PA to PB B O P <P OP = P A P > P A PA <PB O P = PR A B Р > PA PB P<PB P₁ = PB A O O O B P > P A B
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