Here is a sketch of a 3d 22 orbital:х —уThis sketch is about 1800pm wide.The coordinate (x, y, and z) axes are also shown.You can rotate the sketch for a better view of the orbital by dragging the slider with your mouse.Suppose an atom with its nucleus at the origin has an electron in a 3d2 orbital. Complete each row of the table below by deciding how P, the2x -yA'probability of finding the electron at point A, compares to PB'the probability of finding the electron at point B.point Apoint Bcompare PA to PBР. <РВA`P200 pm to the right of the nucleus, along the +x axis.200 pm to the left of the nucleus, along the -x axis.A = PB> PPAВP200 pm behind the nucleus, along the +y axis.PA= PB200 pm in front of the nucleus, along the -y axis.> PAP< PA= PBP200 pm above the nucleus, along the +z axis.200 pm below the nucleus along the -z axis.P> PA

For d orbitals, the quantum number (principal quantum number )is n=3 and l(angular quantum number…

Here is a sketch of a 3d orbital: 2 This sketch is about 1800 pm wide. The coordinate (x, y, and z) axes are also shown. You can rotate the sketch for a better view of the orbital by dragging the slider with your mouse. Suppose an atom with its nucleus at the origin has an electron in a 3d 2 orbital. Complete each row of the table below by deciding how P A' probability of finding the electron at point A, compares to PR, the probability of finding the electron at point B. B' point A point B compare PA to PB O P,< P, 200 pm to the right of the nucleus, along the +x axis. 200 pm to the left of the nucleus, along the -x axis. O P,= PB P > P, B P < P B 200 pm behind the nucleus, along the +y axis. 200 pm in front of the nucleus, along the -y axis. P,= PB O P,> P, B < P B P= PB 200 pm above the nucleus, along the +z axis. 200 pm below the nucleus along the -z axis. O P,> P, A

Here is a sketch of a 3d orbital: 2 This sketch is about 1800 pm wide. The coordinate (x, y, and z) axes are also shown. You can rotate the sketch for a better view of the orbital by dragging the slider with your mouse. Suppose an atom with its nucleus at the origin has an electron in a 3d 2 orbital. Complete each row of the table below by deciding how P A' probability of finding the electron at point A, compares to PR, the probability of finding the electron at point B. B' point A point B compare PA to PB O P,< P, 200 pm to the right of the nucleus, along the +x axis. 200 pm to the left of the nucleus, along the -x axis. O P,= PB P > P, B P < P B 200 pm behind the nucleus, along the +y axis. 200 pm in front of the nucleus, along the -y axis. P,= PB O P,> P, B < P B P= PB 200 pm above the nucleus, along the +z axis. 200 pm below the nucleus along the -z axis. O P,> P, A

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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i 1 Z I 1 1 X 1 This sketch is about 1800 pm wide. The coordinate (x, y, and z) axes are also shown. You can rotate the sketch for a better view of the orbital by dragging the slider with your mouse. Suppose an atom with its nucleus at the origin has an electron in a 3d, orbital. Complete each row of the table below by deciding how PA the probability c finding the electron at point A, compares to PB, the probability of finding the electron at point B. point A 200 pm in front of the nucleus, along the -y axis. 200 pm above the nucleus, along the +z axis. 200 pm to the right of the nucleus, along the +x axis. point B 200 pm behind the nucleus, along the +y axis. 200 pm below the nucleus along the -z axis. 200 pm to the left of the nucleus, along the -x axis. compare PA to PB B O P P A PA PA PB P P A B
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Q2
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