Suppose an atom with its nucleus at the origin has an electron in a 2p, orbital. Complete each row of the table below by deciding how P, the probability of finding the electron at point A, compares to PR, the probability of finding the electron at point B. point A point B compare PA to Pe 100 pm above the nucleus, along the +z axis. 100 pm to the right of the nucleus, along the +x axis. P = P, O P, > P, O PA 100 pm behind the nucleus, along the +y axis. 100 pm to the left of the nucleus, along the -x axis. O P, = PR O P, > P, P,< P 100 pm below the nucleus along the -z axis. 100 pm in front of the nucleus, along the -y axis. P = P, B
Suppose an atom with its nucleus at the origin has an electron in a 2p, orbital. Complete each row of the table below by deciding how P, the probability of finding the electron at point A, compares to PR, the probability of finding the electron at point B. point A point B compare PA to Pe 100 pm above the nucleus, along the +z axis. 100 pm to the right of the nucleus, along the +x axis. P = P, O P, > P, O PA 100 pm behind the nucleus, along the +y axis. 100 pm to the left of the nucleus, along the -x axis. O P, = PR O P, > P, P,< P 100 pm below the nucleus along the -z axis. 100 pm in front of the nucleus, along the -y axis. P = P, B
Related questions
Question
Transcribed Image Text:Suppose an atom with its nucleus at the origin has an electron in a 2p, orbital. Complete each row of the table below by deciding how P
A'
the probability of
finding the electron at point A, compares to P
the probability of finding the electron at point B.
B'
point A
point B
compare PA to PB
O 'A
< P
В
P
= P
100 pm above the nucleus, along the +z axis.
100 pm to the right of the nucleus, along the +x axis.
A
В
Р> Р.
A
В
A
В
P
= P
100 pm behind the nucleus, along the +y axis.
100 pm to the left of the nucleus, along the -x axis.
A
В
Р. > Р.
A
В
P
<Р.
В
A
100 pm below the nucleus along the -z axis.
100 pm in front of the nucleus, along the -y axis.
= P
A
В
Р> Р
A
В
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 3 steps
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.