ΟOΖ • ΣΒΩ-j3 ΩO a. Zτ = 1,95 + j1,29 ΩΟb. Ζτ = 1,95 - j0,29 ΩO20ww4Ω;d. Zτ = 1,95 - j1,29 Ωj2 Ωe. Zτ = 1,95 + j0,29 Ω= -13 Ωc. None of the alternatives are correct3 ΩΜ4Ω

Simplified circuit for total impedance ZT :

Answered: Z 3D 20 www 40 -j3 n O d. Z 1,95 -j1,29…

Z 3D 20 www 40 -j3 n O d. Z 1,95 -j1,29 = O e. Z 1,95 + j0,29 0 j3 n j20 -j30 O a. Z₁ = 1,95 +j1,29 O b. Z 1,95 -j0,29 O c. None of the alternatives are correct 40

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Concept explainers

Superposition Theorem

The superposition theorem is applied to linear systems. For such systems, the output from two different inputs equals the sum of the outputs from each input separately. On applying this theorem many times we get the output from any number of inputs equal to the sum of the outputs from the individual inputs separately.

Question

Ο
O
Ζ • ΣΒΩ
-j3 Ω
O a. Zτ = 1,95 + j1,29 Ω
Ο
b. Ζτ = 1,95 - j0,29 Ω
O
20
ww
4Ω;
d. Zτ = 1,95 - j1,29 Ω
j2 Ω
e. Zτ = 1,95 + j0,29 Ω
= -13 Ω
c. None of the alternatives are correct
3 Ω
Μ
4Ω

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