y(t)=y0+vy0t-0.5gt2 1) Using algebra shows that a meteor, initially at rest (vy0=0) will take about 20 minutes to fall from an altitude of 7,000 km as shown in the diagram to the right. Note that the change in y is negative and you will need to convert km into meters for the units to work out correctly. The calculation from problem 1) is incorrect though. The reason being that acceleration is not constant. The acceleration due to gravity varies with height. When near the surface of the Earth objects accelerate at g = 9.8 m/s2 however when the meteor is further away from the Earth it’s the acceleration is less. The meteors acceleration is actually given by the formula. ay=-G(M/r2)

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y(t)=y0+vy0t-0.5gt2

1) Using algebra shows that a meteor, initially at rest
(vy0=0) will take about 20 minutes to fall from an altitude
of 7,000 km as shown in the diagram to the right. Note that
the change in y is negative and you will need to convert km
into meters for the units to work out correctly.


The calculation from problem 1) is incorrect though. The
reason being that acceleration is not constant. The
acceleration due to gravity varies with height. When near the
surface of the Earth objects accelerate at g = 9.8 m/s2 however when the meteor is further away from the Earth it’s
the acceleration is less. The meteors acceleration is actually given by the formula.

ay=-G(M/r2)

Meteor!
y= 7,000 km
Py = 0 km
R= 6,371 km
Earth
令
Transcribed Image Text:Meteor! y= 7,000 km Py = 0 km R= 6,371 km Earth 令
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