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Your Question: Write a program in MARIE assembler to print “Hello World!”  Define the message as a “C” style NULL terminated string. The program must implement a loop,  like the pseudocode below. str =“Hello World!”   index = 0 while str[index] != 0      output str[index]       index = index + 1   ORG 100 START,  LOAD STR         STORE INDEX LOOP,   LOAD INDEX         ADD ONE         STORE INDEX         LOAD INDEX         ADD STR         STORE X         LOAD X         OUTPUT         JUMP END           JUMP LOOP END,    HALT STR,    HEX 0048         HEX 0065         HEX 006C         HEX 006C         HEX 006F         HEX 0020         HEX 0057         HEX 006F         HEX 0072         HEX 006C         HEX 0064         HEX 0021         HEX 0000 INDEX,  DEC 0 ONE,    DEC 1 X,      DEC 0 END  START   // it does not print anything, help pls

Your Question: Write a program in MARIE assembler to print “Hello World!”  Define the message as a “C” style NULL terminated string. The program must implement a loop,  like the pseudocode below. str =“Hello World!”   index = 0 while str[index] != 0      output str[index]       index = index + 1   ORG 100 START,  LOAD STR         STORE INDEX LOOP,   LOAD INDEX         ADD ONE         STORE INDEX         LOAD INDEX         ADD STR         STORE X         LOAD X         OUTPUT         JUMP END           JUMP LOOP END,    HALT STR,    HEX 0048         HEX 0065         HEX 006C         HEX 006C         HEX 006F         HEX 0020         HEX 0057         HEX 006F         HEX 0072         HEX 006C         HEX 0064         HEX 0021         HEX 0000 INDEX,  DEC 0 ONE,    DEC 1 X,      DEC 0 END  START   // it does not print anything, help pls

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Your Question:
Write a program in MARIE assembler to print “Hello World!” 
Define the message as a “C” style NULL terminated string.
The program must implement a loop,  like the pseudocode below.
str =“Hello World!”  
index = 0
while str[index] != 0
     output str[index] 
     index = index + 1
 

ORG 100

START,  LOAD STR
        STORE INDEX
LOOP,   LOAD INDEX
        ADD ONE
        STORE INDEX
        LOAD INDEX
        ADD STR
        STORE X
        LOAD X
        OUTPUT
        JUMP END  
        JUMP LOOP

END,    HALT

STR,    HEX 0048
        HEX 0065
        HEX 006C
        HEX 006C
        HEX 006F
        HEX 0020
        HEX 0057
        HEX 006F
        HEX 0072
        HEX 006C
        HEX 0064
        HEX 0021
        HEX 0000

INDEX,  DEC 0
ONE,    DEC 1
X,      DEC 0

END  START

 
// it does not print anything, help pls 
**Code Table** | Type | Instruction | Hex Opcode | Summary | |--------------------|-------------|------------|--------------------------------------------------------------------------------------------------| | **Arithmetic** | Add X | 3 | Adds value in AC at address X into AC, AC ← AC + X | | | Subt X | 4 | Subtracts value in AC at address X into AC, AC ← AC - X | | | AddI X | B | Add Indirect: Use the value at X as the actual address of the data operand to add to AC | | | Clear | A | AC ← 0 | | **Data Transfer** | Load X | 1 | Loads Contents of Address X into AC | | | Store X | 2 | Stores Contents of AC into Address X | | **I/O** | Input | 5 | Request user to input a value | | | Output | 6 | Prints value from AC | | **Branch** | Jump X | 9 | Jumps to Address X | | | Skipcond (C)| 8 | Skips the next instruction based on C: if (C) = <br>- 000: Skips if AC < 0<br>- 400: Skips if AC = 0<br>- 800: Skips if AC > 0 | | **Subroutine** | JnS X | 0 | Jumps and Store: Stores value of PC at address X then increments PC to X+1 | | | JumpI X | C | Uses the value at X as the address to jump to | | **Indirect Addressing** | LoadI | D | Loads value from indirect address into AC <br>e.g. LoadI addresspointer <br>Gets address value from addresspointer, loads value at the address into AC| | | StoreI | E | Stores value in AC at the indirect address <br>e.g. StoreI addresspointer <br>Gets value from addresspointer, stores the AC value into the address | | **Halt** | Halt | 7 | End the program |
Transcribed Image Text:**Code Table** | Type | Instruction | Hex Opcode | Summary | |--------------------|-------------|------------|--------------------------------------------------------------------------------------------------| | **Arithmetic** | Add X | 3 | Adds value in AC at address X into AC, AC ← AC + X | | | Subt X | 4 | Subtracts value in AC at address X into AC, AC ← AC - X | | | AddI X | B | Add Indirect: Use the value at X as the actual address of the data operand to add to AC | | | Clear | A | AC ← 0 | | **Data Transfer** | Load X | 1 | Loads Contents of Address X into AC | | | Store X | 2 | Stores Contents of AC into Address X | | **I/O** | Input | 5 | Request user to input a value | | | Output | 6 | Prints value from AC | | **Branch** | Jump X | 9 | Jumps to Address X | | | Skipcond (C)| 8 | Skips the next instruction based on C: if (C) = <br>- 000: Skips if AC < 0<br>- 400: Skips if AC = 0<br>- 800: Skips if AC > 0 | | **Subroutine** | JnS X | 0 | Jumps and Store: Stores value of PC at address X then increments PC to X+1 | | | JumpI X | C | Uses the value at X as the address to jump to | | **Indirect Addressing** | LoadI | D | Loads value from indirect address into AC <br>e.g. LoadI addresspointer <br>Gets address value from addresspointer, loads value at the address into AC| | | StoreI | E | Stores value in AC at the indirect address <br>e.g. StoreI addresspointer <br>Gets value from addresspointer, stores the AC value into the address | | **Halt** | Halt | 7 | End the program |
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