1. Your free body diagram for Part 1 should have looked it this.Drag and drop the heads and tails of the vectors to construct the free-body diagram.Note: the applied force directed to the right.Note: the angles may be within +15°, and the magnitudes are not considered.frie; 180°a =N: 90°am/s²mg; 270°Suppose you have a 120-kg wooden crate resting on a wood floor. Use μ = 0.5 and μ = 0.3.F:0º(b) What is the maximum force you can exert horizontally on the crate without moving it?FmaxN(c) If you continue to exert this force once the crate starts to slip, what will its accelerationthen be?

Given that: The mass of the wooden block is m=120 kg. The coefficient of kinetic and static…

Your free body diagram for Part 1 should have looked it this. Drag and drop the heads and tails of the vectors to construct the free-body diagram. Note: the applied force is directed to the right. Note: the angles may be within +15°, and the magnitudes are not considered. = frie; 180° a = N; 90° a Suppose you have a 120-kg wooden crate resting on a wood floor. Use μ= 0.5 and μ = 0.3. m/s² mg; 270° (b) What is the maximum force you can exert horizontally on the crate without moving it? F max N F:0º (c) If you continue to exert this force once the crate starts to slip, what will its acceleration then be?

Your free body diagram for Part 1 should have looked it this. Drag and drop the heads and tails of the vectors to construct the free-body diagram. Note: the applied force is directed to the right. Note: the angles may be within +15°, and the magnitudes are not considered. = frie; 180° a = N; 90° a Suppose you have a 120-kg wooden crate resting on a wood floor. Use μ= 0.5 and μ = 0.3. m/s² mg; 270° (b) What is the maximum force you can exert horizontally on the crate without moving it? F max N F:0º (c) If you continue to exert this force once the crate starts to slip, what will its acceleration then be?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Please show the solutions clearly and box the final answers. Provide the necessary explanationsfor the solutions. Showthe necessary diagrams/free-body diagrams.
In , the man has a mass of 65 kg and the crate has a mass of 110 kg. The coefficient of static friction between his shoes and the ground is μs = 0.4 and between the crate and the ground is μc = 0.3. A) Determine if the man is able to move the crate using the rope-and-pulley system shown. B) Prove your answer to part A by calculating the static frictional force F�between the man's shoes and the ground required to move the crate and the maximum static frictional force Fmax which can be developed. Express your answers in newtons to three significant figures separated by a com_ma.
1. Your free body diagram for Part 1 should have looked it this. F. max Drag and drop the heads and tails of the vectors to construct the free-body diagram. Note: the applied force is directed to the right. Note: the angles may be within ±15°, and the magnitudes are not considered. = Suppose you have a 120-kg wooden crate resting on a wood floor. Use µg = 0.5 and μ = 0.3 . Assume all quantities are correct to 3 significant figures. a = 1.96 ffric; 180° (b) What is the maximum force you can exert horizontally on the crate without moving it? Enter to 3 significant figures ✔N N: 90° a m/s² mg; 270° F:0° (c) If you continue to exert this force once the crate starts to slip, what will its acceleration then be? Enter to 3 significant figures
Help on section C
Consider the system in the picture below: a cart of mass M with a static friction coefficient u is connected through a massless string to a hanging mass m. M is a capital letter, m is lower case. Write them as such, or vour equations will be confusing, M We want to find the maximum value of the hanging mass m such that the system is in equilibrium. 1. Free body diagram (FBD): Draw a FBD for each: the Cart and the hanging mass. Clearly show all the forces. 2. Clearly write the equilibrium equations for the cart in the horizontal and vertical direction. 3. Clearly write the equilibrium equation for the hanging mass. 4. Solve the system of the three equations above for the hanging mass m. Show your calculation to get credit. 5. What would happen if mass m exceeds this value? Explain.
Block 1 (20 kg) is pulled by a rope from left to right up a ramp which is inclined 50 degrees from the horizontal. The rope pulls on block 1 with a force of 400 N parallel to the surface of the inclined plane. The coefficient of kinetic friction between the block and the surface equals 0.4. (use g = 10 m/s2) On a sheet of paper, draw the free body diagram for block 1 using the two-subscript notation from class.Assume that the x-axis is parallel to the incline and positive in the direction up the incline.After completing the free body diagram, enter below each force and its x & y-components. FORCES on BLOCK 1 Weight force on block 1 by Earth W1E = i + j N Tension force on block 1 by Rope T1R = i + j N Normal force on block 1 by Surface N1S = i + j N Frictional force on block 1 by Surface f1S = i + j N What is the acceleration a of block 1? a = i + j m/s2
Please draw the free diagram clear and also add any force
i would like some help with my homework please . im having trouble.
Find I and J values and please answer all parts of this question 3. Block 1 (10 kg) is setting on the floor of an elevator. The elevator is moving upward with an increasing speed and the magnitude of the acceleration is 2 m/s2. On a sheet of paper, draw the free body diagram for block 1 using the two-subscript notation from class. After completing the free body diagram, enter below each force and its x & y-components. (use g = 10 m/2) Remember that the x-component is the "i" component and the y-component is the "j" component. -NET force on Block 1 (round to nearest integer) Fnet1 = ——- i + ——- j N The DIRECTION of the net force on block 1 is in the same direction as its acceleration. If the elevator is moving upward with an increasing speed, then the direction of the block's acceleration is up (positive y-value). The MAGNITUDE of the net force on block 1 equals its mass times acceleration, which are both given in the problem. -FORCES on BLOCK 1 Weight force on block 1…
please answer all parts of the question
What is the correct free body diagram for the system and what is the rank of the forces from largest to smallest?