Below are six crates at rest on level surfaces. The crates have different masses and the frictional coefficients [given as (us, uk)] between the crates and the surfaces differ. The same external force is applied to each crate, but none of the crates move. Part A Rank the crates on the basis of the frictional force acting on them. Rank from largest to smallest. To rank items as equivalent, overlap them. , View Available Hint(s) |Reset||Help| 750 kg 500 kg 250 kg 600 kg 750 kg 1500 kg L = (0.4, 0.3) p= (0.6. 0.3) µ = (0.2, 0. 1) H= (0.8, 0.5) p = (0.6, 0.5) L= (0.3, 0.1) largest smallest The correct rapking cannot be determined

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Chapter1: Units, Trigonometry. And Vectors
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Below are six crates at rest on level surfaces. The crates have different masses and the frictional coefficients [given as (us, uk)] between the crates and the surfaces differ. The same external force is applied to each crate, but none of the crates move.
Part A
Rank the crates on the basis of the frictional force acting on them.
Rank from largest to smallest. To rank items as equivalent, overlap them.
, View Available Hint(s)
|Reset||Help|
750 kg
500 kg
250 kg
600 kg
750 kg
1500 kg
L = (0.4, 0.3)
p= (0.6. 0.3)
µ = (0.2, 0. 1)
H= (0.8, 0.5)
p = (0.6, 0.5)
L= (0.3, 0.1)
largest
smallest
The correct rapking cannot be determined
Transcribed Image Text:Below are six crates at rest on level surfaces. The crates have different masses and the frictional coefficients [given as (us, uk)] between the crates and the surfaces differ. The same external force is applied to each crate, but none of the crates move. Part A Rank the crates on the basis of the frictional force acting on them. Rank from largest to smallest. To rank items as equivalent, overlap them. , View Available Hint(s) |Reset||Help| 750 kg 500 kg 250 kg 600 kg 750 kg 1500 kg L = (0.4, 0.3) p= (0.6. 0.3) µ = (0.2, 0. 1) H= (0.8, 0.5) p = (0.6, 0.5) L= (0.3, 0.1) largest smallest The correct rapking cannot be determined
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