Your character starts at position po with initial velocity Each frame, it moves with constant acceleration a. Compute the position of the character with given the parameters. = 4 0 What is Pi when po = (4),d = (^,),ä = ( ₂ ) ₁ ||d || and St = 0.23?
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- Sketch or computer plot a graph of the function y = e−x2.Vector C has x-component -1.54 and a y-component -4.53. What is the angle measured counter clock wise from +x axis in degrees. Specify answer to one decimal.Given the acceleration as a function of the angle theta, a =6.5sinθ + 2.3cosθ. Find the optimal angle, so the acceleration is maximum Find the value of the maximum acceleration I have found the derivative of the function but am confusing myself on the next steps.
- If u = (-1, 1, 1) and i = (0,0, 0), find the length and direction of u x i and i x ủ. Length of u x i is Direction of ủ x ở is (If ů x ủ does not have a direction, enter "none".) Length of i xu is ... Direction of v xũ is (If v xu does not have a direction, enter "none".)Could you look number 8?I need some help with finding the velocity in section 1.1, and also solving 1.2. I believe the projection angle is 45 degrees. Thanks!
- Consider a non-stationary time series is defined as below Yt = B0 +B1t+et Where et is error term and IID in nature. Prove that 1st difference of this series is stationary.If ů = (7,–6, 0) and i = (1, 1,0), find the length and direction of ủ x i and i x ū. Length of u x i is ... ... Direction of u xở is (If u X v does not have a direction, enter "none".) Length of i x ủ is Direction of ú xũ is (If i xủ does not have a direction, enter "none".)In certain physical models, the nonhomogeneous term, or forcing term, g(t) in the equation ay" + by' + cy = g(t) may not be continuous, but have a jump discontinuity. If this occurs, a reasonable solution can still be obtained using the following procedure. Consider the following initial value problem. 240 if 0sts7T/6 y" + 4y' + 40y = g(t); y(0) = 0, y'(0) = 0, where g(t) = . if t> 7x/6 Complete parts (a) through (c) below. (a) Find a solution to the initial value problem for 0 sts 71/6. The solution for 0sts 7n/6 is y(t) = - 6 e -21 *cos 6t - 2 e - 2t sin 6t + 6 (Type an equation.) (b) Find a general solution for t> 71/6. The general solution for t> 7x/6 is y(t) = C, e-2 cos 6t + C, e -2t sin 6t (Type an equation. Do not use d. D. e, E, i, or I as arbitrary constants since these letters already have defined meanings.) (c) Now choose the constants in the general solution from part (b) so that the solution from part (a) and the solution from part (b) agree, together with their first…
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