You wish to test the following claim (Ha) at a significance level of a = 0.01.Ho:Pi P2H4 Pi< P2You obtain 73.8% successes in a sample of size n, = 629 from the first population. You obtain 76% successes in asample of size n2you should use the normal distribution as an approximation for the binomial distribution.601 from the second population. For this test, you should NOT use the continuity correction, andWhat is the test statistic for this sample? (Report answer accurate to three decimal places.)= -0.917test statisticWhat is the p-value for this sample? (Report answer accurate to four decimal places.)p-value = 0.1796The p-value 1s..less than (or equal to)greater than oThis test statistic leads to a decision to.reject the nullthe nullaccepta N)

Given Data and calculation is shown below

Answered: You wish to test the following claim…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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I need help with the second half of C ONLY. A random sample of 50 binomial trials resulted in 20 successes. Test the claim that the population proportion of successes does not equal 0.50. Use a level of significance of 0.05. (a) Can a normal distribution be used for the distribution? Explain. No, n·q is greater than 5, but n·p is less than 5.Yes, n·p and n·q are both greater than 5. No, n·p is greater than 5, but n·q is less than 5.No, n·p and n·q are both less than 5.Yes, n·p and n·q are both less than 5. (b) State the hypotheses. H0: p = 0.5; H1: p > 0.5H0: p = 0.5; H1: p ≠0.5 H0: p < 0.5; H1: p = 0.5H0: p = 0.5; H1: p < 0.5 (c) Compute . (Enter a number.)p hat = Compute the corresponding standardized sample test statistic. (Enter a number. Round your answer to two decimal places.)
If The test statistic ofz=−1.45is obtained when testing the claim thatp
You wish to test the following claim (Ha) at a significance level of a = 0.005. Ho: p = 0.78 Ha: p > 0.78 You obtain a sample of size n = 621 in which there are 508 successful observations. For this test, you should use the (cumulative) binomial distribution to obtain an exact p-value. (Do not use the normal distribution as an approximation for the binomial distribution.) The p-value for this test is (assuming Ho is true) the probability of observing... O at most 508 successful observations O at least 508 successful observations What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = The p-value is... O less than (or equal to) a greater than a This test statistic leads to a decision to... reject the null accept the null O fail to reject the null
Answers: 2. t = .656, do not reject Ho: there is no evidence that this year's students are performing differently than students in previous years. 3. chi-square = 7.997, Do not reject H0; no evidence that the variance is significantly less than 175. chi-square = 11.250, Do not reject H0; no evidence that the variance is significantly greater than 175. 4. 3.973 to 13.5219
Test the claim below about the mean of the differences for a population of paired data at the level of significance a. Assume the samples are random and dependent, and the populations are normally distributed. Claim: H, =0; a= 0.05. Sample statistics: d = 3.2, s, =8.49, n= 9 Identify the null and alternative hypotheses. Choose the correct answer below. O A. Hg: Has0 O B. Ho: Hg #0 H: H >0 Hg: Hg =0 O C. Ho: Ha 0 H: Hg sO O E. Hg: Ha20 F. Hoi Ha =0 H: Hg #0 The test statistic is t= 1.13. (Round to two decimal places as needed.) The critical value(s) is(are) to =-2.31,2.31. (Round to two decimal places as needed. Use a comma to separate answers as needed.) Since the test statistic is the rejection region, V the null hypothesis. There V statistically significant evidence to reject the claim.
You wish to test the following claim (Ha) at a significance level of a = 0.002. Ho: p= 0.6 Ha:p> 0.6 You obtain a sample of size n = 176 in which there are 117 successful observations. For this test, you should use the (cumulative) binomial distribution to obtain an exact p-value. (Do not use the normal distribution as an approximation for the binomial distribution.) The p-value for this test is (assuming Ho is true) the probability of observing... at most 117 successful observations at least 117 successful observations What is the p-value for this sample? (Report answer accurate to four decimal places.) P-value= The p-value is... less than (or equal to) a Ogreater than a This test statistic leads to a decision to... O reject the null O accept the null fail to reject the null As such, the final conclusion is that... There is sufficient evidence warrant rejection of the claim that the population proportion is greater than 0.6. There is not sufficient evidence to warrant rejection of the…
Suppose you had obtained a test statistic of 2.45 (this is incorrect). What would the P-value be? Draw a conclusion based on a = 0.01. Select one: O a. 0.01 < P-value < 0.02, we fail to reject Ho and do not have sufficient evidence to conclude that the mean difference in LDL from switching from an omnivorous to a plant-based diet for 6 weeks is not the same for men and women. O b. 0.005 < P-value < 0.01, we fail to reject Ho and do not have sufficient evidence to conclude that the mean difference in LDL from switching from an omnivorous to a plant-based diet for 6 weeks is not the same for men and women. O c. 0.01 < P-value < 0.02, we reject Ho and have sufficient evidence to conclude that the mean difference in LDL from switching from an omnivorous to a plant-based diet for 6 weeks is not the same for men and women. O d. 0.005 < P-value < 0.02, we reject Ho and have sufficient evidence to conclude that the mean difference in LDL from switching from an omnivorous to a plant-based diet…
You wish to test the following claim (Ha) at a significance level of a = 0.05. Ho:p = 0.57 Ha:p # 0.57 You obtain a sample of size n = 452 in which there are 232 successful observations. For this test, you should NOT use the continuity correction, and you should use the normal distribution as an approximation for the binomial distribution. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = The p-value is... O less than (or equal to) a greater than a This test statistic leads to a decision to... O reject the null O accept the null O fail to reject the null As such, the final conclusion is that.... There is sufficient evidence to warrant rejection of the claim that the population proportion is not equal to 0.57. There is not sufficient evidence to warrant rejection of the claim that the population proportion is not equal to 0.57. The…
help with 3
Test the claim below about the mean of the differences for a population of paired data at the level of significance a. Assume the samples are random and dependent, and the populations are normally distributed. Claim: 0 = 0 E. Ho: Hd 0 Ha: Hd s0 The test statistic is t= 1.43 . (Round to two decimal places as needed.) The critical value(s) is(are) to = (Round to two decimal places as needed. Use a comma to separate answers as needed.)
A poll of 2,115 randomly selected adults showed that 87% of them own cell phones. The technology display below results from a test of the claim that 94% of adults own cell phones. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.01 significance level to complete parts (a) through (e). Test of p = 0.94 vs p *0.94 Sample X N 1 1844 2,115 Sample p 0.871868 95% CI (0.853147,0.890588) a. Is the test two-tailed, left-tailed, or right-tailed? Z-Value - 13.19 P-Value 0.000
I need help with this one please thank you

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