As such, the final conclusion is that...There is sufficient evidence to warrant rejection of the claim that the population mean is greater than 73.8.There is not sufficient evidence to warrant rejection of the claim that the population mean is greater than 73.8.The sample data support the claim that the population mean is greater than 73.8.There is not sufficient sample evidence to support the claim that the population mean is greater than 73.8. You wish to test the following claim (Ha) at a significance level of a = 0.002.H.:µ = 73.8Ha:µ > 73.8You believe the population is normally distributed and you know the standard deviation is o = 16.9. Youobtain a sample mean of M = 77.3 for a sample of size n = 66.What is the critical value for this test? (Report answer accurate to three decimal places.)critical value =What is the test statistic for this sample? (Report answer accurate to three decimal places.)test statistic =The test statistic is...O in the critical regionnot in the critical regionThis test statistic leads to a decision to...O reject the nullaccept the nullO fail to reject the null

Name: As such, the final conclusion is that...There is sufficient evidence t
Uploaded: 2024-03-20T07:07:12.000Z
Channel: Bartleby
Description: As such, the final conclusion is that...There is sufficient evidence to warrant rejection of the claim that the population mean is greater than 73.8.There is not sufficient evidence to warrant rejection of the claim that the population mean is greate

Answered: You wish to test the following claim…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Topic Video

Question

As such, the final conclusion is that...

There is sufficient evidence to warrant rejection of the claim that the population mean is greater than 73.8.
There is not sufficient evidence to warrant rejection of the claim that the population mean is greater than 73.8.
The sample data support the claim that the population mean is greater than 73.8.
There is not sufficient sample evidence to support the claim that the population mean is greater than 73.8.

You wish to test the following claim (Ha) at a significance level of a = 0.002.
H.:µ = 73.8
Ha:µ > 73.8
You believe the population is normally distributed and you know the standard deviation is o = 16.9. You
obtain a sample mean of M = 77.3 for a sample of size n = 66.
What is the critical value for this test? (Report answer accurate to three decimal places.)
critical value =
What is the test statistic for this sample? (Report answer accurate to three decimal places.)
test statistic =
The test statistic is...
O in the critical region
not in the critical region
This test statistic leads to a decision to...
O reject the null
accept the null
O fail to reject the null

Definition Definition Measure of central tendency that is the average of a given data set. The mean value is evaluated as the quotient of the sum of all observations by the sample size. The mean, in contrast to a median, is affected by extreme values. Very large or very small values can distract the mean from the center of the data. Arithmetic mean: The most common type of mean is the arithmetic mean. It is evaluated using the formula: μ = 1 N ∑ i = 1 N x i Other types of means are the geometric mean, logarithmic mean, and harmonic mean. Geometric mean: The nth root of the product of n observations from a data set is defined as the geometric mean of the set: G = x 1 x 2 ... x n n Logarithmic mean: The difference of the natural logarithms of the two numbers, divided by the difference between the numbers is the logarithmic mean of the two numbers. The logarithmic mean is used particularly in heat transfer and mass transfer. ln x 2 − ln x 1 x 2 − x 1 Harmonic mean: The inverse of the arithmetic mean of the inverses of all the numbers in a data set is the harmonic mean of the data. 1 1 x 1 + 1 x 2 + ...

Expert Solution

Step 1

State the hypotheses.

Determine the Critical value.

Use EXCEL Procedure for finding the critical value of z.

Follow the instruction to obtain the critical value of z:

Open EXCEL
Go to Formula bar.
In formula bar enter the function as“=NORMINV”
Enter the probability as 0.999.
Enter the mean as 0 and the Standard deviation as 1.
Click enter

EXCEL output:

From the EXCEL output, the critical value of z at the 99.8% confidence level is 3.090

Thus, the critical value is 3.090.

Step 2

Obtain the value of the test statistic.

The value of the test statistic is obtained below:

Thus, the value of the test statistic is 1.682.

Step by step

Solved in 3 steps with 4 images

Knowledge Booster

$Hypothesis Tests and Confidence Intervals for Means$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.

Similar questions