You wish to test the following claim (\( H_a \)) at a significance level of \( \alpha = 0.002 \).\[H_0: \mu = 82.1\]\[H_a: \mu < 82.1\]You believe the population is normally distributed and you know the standard deviation is \( \sigma = 6.7 \). You obtain a sample mean of \( M = 79.7 \) for a sample of size \( n = 52 \).What is the critical value for this test? (Report answer accurate to three decimal places.)Critical value = \_\_\_\_\_\_What is the test statistic for this sample? (Report answer accurate to three decimal places.)Test statistic = \_\_\_\_\_\_The test statistic is...- [ ] in the critical region- [ ] not in the critical regionThis test statistic leads to a decision to...- [ ] reject the null- [ ] accept the null- [ ] fail to reject the null

Answered: You wish to test the following claim…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A nutritionist claims that the mean tuna consumption by a person is 3.3 pounds per year. A sample of 70 people shows that the mean tuna consumption by a person is 3.1 pounds per year. Assume the population standard deviation is 1.05 pounds. At a = 0.06, can you reject the claim? Ha: p> 3.1 H3: µs3.1 H, µ#3.3 a (b) Identify the standardized test statistic. z= - 1.59 (Round to two decimal places as needed.) (c) Find the P-value. 0.112 (Round to three decimal places as needed.) (d) Decide whether to reject or fail to reject the null hypothesis. O B. Fail to reject Ho. There is not sufficient evidence to reject the claim that mean tuna consumption is equal to 3.3 pounds. A. Reject Ho- There is sufficient evidence to reject the claim that mean tuna consumption is equal to 3.3 pounds. O C. Fail to reject Ho. There is sufficient evidence to reject the claim that mean tuna consumption is equal to 3.3 pounds. O D. Reject Ho There is not sufficient evidence to reject the claim that mean tuna…
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