(a) Identify the claim and state the null and alternative hypotheses.(b) Determine the degrees of freedom, find the critical value, and identify the rejection region.(c) Calculate the test statistic. If convenient, use technology. You want to determine whether the reasons given by workers for continuing their education is related to job type. Inthe study, you randomly collect the data shown in the contingency table. At a= 0.05, can you conclude that thereason and type of worker are dependent? Complete parts (a) through (d).ReasonType of workerProfessional Personal BothTechnicalOther452548444638

Given: The data on the type of worker and the reason to work. The observed frequencies are given as: Type of worker Professional Personal Both Row Total Technical 48 45 44 137 Other 46 25 38 109 Column Total 94 70 82 N=246 The expected(E) frequencies can be calculated as: Eij=Row total of ith row×Column total of jth columnTotal number of samples =Ri×CjNThe expected frequencies for the corresponding observed frequency is given as: E11=R1×C1N =137×94246=52.3495E12=R1×C2N =137×70246=38.9837E13=R1×C3N =137×82246=45.6666E21=R2×C1N =109×94246=41.6504E22=R2×C2N =109×70246=31.0162E23=R2×C3N =109×82246=36.3333 Therefore, the table that can be formed is: Observed frequency (O) Expected frequency (E) (O-E) (O-E)2E 48 52.3495 -4.3495 0.361382 45 38.9837 6.0163 0.928487 44 45.6666 -1.6666 0.060822 46 41.6504 4.3496 0.454234 25 31.0162 -6.0162 1.16696 38 36.3333 1.6667 0.076456 Total 245.9997 0.0003 3.048341(a) The researcher's claim is that the reason and the type of worker are dependent, So the null and alternate hypothesis formed will be: H0: The reason and the type of worker are independent. H1: The reason and type of worker are dependent. (b) The degrees of freedom (df) is given as: df=(r-1)(c-1) =(2-1)(3-1) =2 where r is the number of rows and c is the number of columns. Therefore, the degrees of freedom is 2. From the chi-square table, the critical values at 2 degrees of freedom and at 0.05 level of significance are XL2=0.051 and XU2=7.378 Rejection region (R.R) is : R.R>7.378 and R.R<0.051 (c) The value of test statistics is given as: X2=∑i(Oi-Ei)2Ei =3.0483 Therefore, the calculated value of test statistics is 3.0483. Since, the calculated value (=3.0483) falls between the critical values(=0.051 and 7.378), In this case, the value lies in the non rejection region and the null hypothesis fails to reject. As a conclusion, there is not sufficient evidence to conclude that the reason and the type of worker are dependent.