1. If 25.0 mL of 0.1000 M HCl is titrated with NaOH with an initial volume of 3.02 mL and final volume of 24.10 mL, what is the concentration of the NaOH (in M)?
1. If 25.0 mL of 0.1000 M HCl is titrated with NaOH with an initial volume of 3.02 mL and final volume of 24.10 mL, what is the concentration of the NaOH (in M)?
ANSWER: 0.1186
2. In the second titration, the molar mass of an unknown monoprotic acid is calculated.
If 0.100 grams of unknown solid are dissolved in water and titrated with 4.68 mL of the NaOH, what is the molar mass of the solid?
HINTS:
Molar mass is grams / moles. We have grams from the weighed mass, we can calculate moles of acid from the titration.
Monoprotic means that it produces 1 H+ per molecule. This means that our moles of NaOH added and moles of acid are the same.
You will need to use your concentration of NaOH from the previous question
3. In the final titration, the amount of salicylic acid (the active ingredient) in aspirin is calculated.
If 0.1000 grams of aspirin tablets are dissolved in water and titrated with the NaOH from an initial volume of 15.90mL to a final volume of 18.80mL, what is the % mass of salicylic acid in the aspirin?
HINTS:
- You will need to use your NaOH concentration from the 1st question
- Mass percent here would be mass of (salicylic acid/mass of aspirin) x 100%
- You will need to use the molar mass of salicylic acid
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2. In the second titration, the molar mass of an unknown monoprotic acid i
If 0.100 grams of unknown solid are dissolved in water and titrated with 4.68 mL of the NaOH, what is the molar mass of the solid?
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In the second titration, the molar mass of an unknown monoprotic acid is calculated.
If 0.100 grams of unknown solid are dissolved in water and titrated with 4.68 mL of the NaOH, what is the molar mass of the solid?
HINTS:
- Molar mass is grams / moles. We have grams from the weighed mass, we can calculate moles of acid from the titration.
- Monoprotic means that it produces 1 H+ per molecule. This means that our moles of NaOH added and moles of acid are the same.
- You will need to use your concentration of NaOH from the previous question