You run this reaction and isolate the actual product. The actual product only shows a strong signal at ~1100 cm-1; thus, there are no other significant/key signals observed in the IR spectrum (which infers no other functionality is present).  The MF of the actual product is C6H12O. Given all information here, check all that are true a.the product's degrees of unsaturation is the same as the reactant's   b.the bromine remains in the product   c.the strong IR signal confirms a C-O bond   d.the product's degrees of unsaturation is different from the reactant's   e.the strong IR signal confirms the C-Br bond   f.no alcohol is present in the product   g.the bromine is absent in the product   h.an alcohol product has formed   i.the ketone did not react and remains in the product

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NMR Spectroscopy

NMR stands for Nuclear Magnetic Resonance in which the study of different molecules is done based on the interaction of radiofrequency electromagnetic radiations with the nuclei of molecules placed in a strong magnetic field. A precise study of spectra of visible light and all bands of electromagnetic radiation is called spectroscopy.