The image depicts a problem from a spectroscopy exercise aimed at determining the structure of a compound with the chemical formula \( \text{C}_{10}\text{H}_{14}\text{O} \) based on a given NMR spectrum. The exercise requires filling out a table and identifying the final structure.### NMR Spectrum Analysis:The spectrum displays peaks at various chemical shifts, each labeled with a signal (A through E), integration values, and splitting patterns.#### Key Features:- **Signal A:** - Integration: 3H - **Signal B:** - Integration: 2H - **Signal C:** - Integration: 3H - **Signal D:** - Integration: 1H - **Signal E:** - Integration: 5H#### Chemical Shift (PPM):- A: Close to 1.0- B: Around 1.5- C: Near 2.0- D: Approximately 4.0- E: About 7.0### Table Format:Below is a template for students to fill in based on the spectrum analysis:| Signal | Integration | Chemical Shift | Splitting | Possible Fragment ||--------|-------------|----------------|-----------|-------------------|| A | 3H | | | || B | 2H | | | || C | 3H | | | || D | 1H | | | || E | 5H | | | |### Final Structure:The task concludes with deducing the final chemical structure of the compound, using the information from the table and the spectrum.This exercise helps students apply their understanding of NMR spectroscopy in practical scenarios, encouraging critical thinking and problem-solving in organic chemistry.

Answered: 5. Determine the structure of the…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Related questions

Concept explainers

Question

The image depicts a problem from a spectroscopy exercise aimed at determining the structure of a compound with the chemical formula \( \text{C}_{10}\text{H}_{14}\text{O} \) based on a given NMR spectrum. The exercise requires filling out a table and identifying the final structure.

### NMR Spectrum Analysis:
The spectrum displays peaks at various chemical shifts, each labeled with a signal (A through E), integration values, and splitting patterns.

#### Key Features:
- **Signal A:**
- Integration: 3H

- **Signal B:**
- Integration: 2H

- **Signal C:**
- Integration: 3H

- **Signal D:**
- Integration: 1H

- **Signal E:**
- Integration: 5H

#### Chemical Shift (PPM):
- A: Close to 1.0
- B: Around 1.5
- C: Near 2.0
- D: Approximately 4.0
- E: About 7.0

### Table Format:
Below is a template for students to fill in based on the spectrum analysis:

| Signal | Integration | Chemical Shift | Splitting | Possible Fragment |
|--------|-------------|----------------|-----------|-------------------|
| A | 3H | | | |
| B | 2H | | | |
| C | 3H | | | |
| D | 1H | | | |
| E | 5H | | | |

### Final Structure:
The task concludes with deducing the final chemical structure of the compound, using the information from the table and the spectrum.

This exercise helps students apply their understanding of NMR spectroscopy in practical scenarios, encouraging critical thinking and problem-solving in organic chemistry.

Expert Solution

Step 1: Explanation

For the interpretation of 1H NMR spectra, few basic points you should remember.

More electronegative atom attached - proton get deshielded - has high value of chemical shift.
More electropositive atom or normal carbon atom- protons get shielded - less chemical shift value.
Aromatic protons falls in the range of 6-8 ppm.
Normal alkane type protons falls in the range of 0.5 - 4.0 ppm depending upon the atom attached near to them.

Step by step

Solved in 2 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Similar questions