You place an object 20.4 cm in front of a diverging lens which has a focal length with a magnitude of 13.0 cm. Determine how far in front of the lens the object should be placed in order to produce an image that is reduced by a factor of 3.20.
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You place an object 20.4 cm in front of a diverging lens which has a focal length with a magnitude of 13.0 cm. Determine how far in front of the lens the object should be placed in order to produce an image that is reduced by a factor of 3.20.
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- An object of height 10.0 cm is placed 20.0 cm away from a converging lens. The image is 30.0 cm high. One can conclude that the focal length of the lens can be (A) 12.0 cm only. (B) either 12.0 cm or 60.0 cm. (C) 15.0 cm only. (D) either 15.0 cm or 30.0 cm.On one side of a diverging lens of focal length 59.0 cm, you position an object of height 3.92 cm somewhere along the principal axis. The resultant image has a height of 2.74 cm. How far from the lens is the object located? 17.8 cm 25.4 cm 43.2 cm 33.0 cmYou place an object 21.2 cm in front of a diverging lens which has a focal length with a magnitude of 12.2 cm. Determine how far in front of the lens the object should be placed in order to produce an image that is reduced by a factor of 2.70.cm
- A system of two converging lenses forms an image of an arrow as shown. The first lens is located at x = 0 and has a focal length of f₁ = 8.8 cm. The second lens is located at x = x2 = 58.13 cm and has a focal length of f2 = 21 cm. The tip of the object arrow is located at (x,y) = (xo,Y)= (-12.3 cm, 6.9 cm). AY (X,Y) 1) What is x₁, the x-coordinate of image of the arrow formed by the first lens? cm Submit 2) What is y₁, the y-coordinate of the image of the tip of the arrow formed by the first lens? cm Submit Virtual and Inverted Virtual and Upright Submit X₂ cm Submit X 3) What is x3, the x co-ordinate of image of the arrow formed by the two lens system? cm Submit 5) What is the nature of the final image relative to the object? Real and Inverted Real and Upright ++++ 4) What is y3, the y-coordinate of the image of the tip of the arrow formed by the two lens system? + 6) Which of the following changes to the locations of the lenses would result in a virtual and inverted image of the…An object is placed to the left of a lens, and a real image is formed to the right of the lens. The image is inverted relative to the object and is one-half the size of the object. The distance between the object and the image is 73.0 cm. (a) How far from the lens is the object? (b) What is the focal length of the lens? (a) do = (b) f=You place an object 24.8 cm in front of a diverging lens which has a focal length with a magnitude of 11.0 cm. Determine how far in front of the lens the object should be placed in order to produce an image that is reduced by a factor of 2.95.
- The distance between the eyepiece and the objective lens in a certain compound microscope is 10.4 cm. The focal length of the objective is 0.430 cm, and that of the eyepiece is 1.40 cm. Find the overall magnification of the microscope. (The near point of the eye is 25 cm. Assume that the object is placed at the focal point of the objective lens, and one places the eyepiece at the near point of the eye.)An object is 21 cm in front of a diverging lens that has a focal length of -9.6 cm. How far in front of the lens should the object be placed so that the size of its image is reduced by a factor of 2.6?You place an object 21.4 cm in front of a diverging lens which has a focal length with a magnitude of 11.8 cm. Determine how far in front of the lens the object should be placed in order to produce an image that is reduced by a factor of 3.35. cm Additional Materials
- An object is placed 21.2 cm in front of a diverging lens which has a focal length with a magnitude of 13.0 cm. How far in front of the lens should the object be placed in order to produce an image that is reduced by a factor of 3.15?A system of two lenses forms an image of an arrow at x = x3 = 57.4 cm. The first lens is a diverging lens located at x = 0 and has a focal length of magnitude f₁ = 11.5 cm. The second lens is located at x = x₂ = 25.4 cm and has an unknown focal length. The tip of the object arrow is located at (x,y) = (xo, Yo) = (-36 cm, 20.6 cm). (x,y) 1) What is x₁, the x-coordinate of image of the arrow formed by the first lens? cm Submit 2) What is y₁, the y-coordinate of the image of the tip of the arrow formed by the first lens? cm Submit X₂ Real and Inverted Real and Upright Virtual and Inverted Virtual and Upright cm Submit (+) 3) What is f2, the focal length of the second lens. If the lens is a converging lens, f2 is positive. If the lens is a diverging lens, f2 is negative. cm Submit + 4) What is y3, the y-coordinate of the image of the tip of the arrow formed by the two lens system? (+ 5) The positions of the two lenses are now interchnaged (i.e., the second lens is moved to x = 0 and the…On one side of a converging lens of focal length 22.4 cm, you position an object of height 2.39 cm somewhere along the principal axis. The resultant image has a height of 11.95 cm. How far from the lens is the object located?