### Problem Statement: Motion of a Crate on an Inclined RampYou managed to pull a heavy crate up a ramp on a truck. The crate has a mass of 48 kg. You were pulling with 464 N of force along the ramp while the ramp made an angle of θ = 29.5 degrees with the horizontal. The coefficient of kinetic friction between the crate and the ramp is 0.45.What is the acceleration of the crate along the ramp?#### Diagram:Below is a diagram illustrating the scenario described:- The ramp is inclined at an angle θ with the horizontal.- The crate is being pulled up the ramp.- The force applied (F_A) is along the surface of the ramp. This force is indicated with a vector pointing upwards along the ramp.![Diagram](https://user-images.githubusercontent.com/2028501/138306183-55eb4f7b-7ff6-407d-beca-bcfffa68110e.png)#### Explanation of Forces and Motion:1. **Gravity (Fg)**: Acts downward with a magnitude of \( F_g = m \cdot g \) (where \( m = 48 \) kg and \( g = 9.81 \) m/s²).2. **Normal Force (N)**: Acts perpendicular to the surface of the ramp.3. **Applied Force (F_A)**: The force pulling the crate up the ramp (464 N).4. **Frictional Force (F_f)**: Opposes the motion, governed by the coefficient of kinetic friction (μ_k = 0.45).5. **Components of Gravity**: - Parallel to the ramp: \( F_{g,\parallel} = F_g \sin(\theta) \) - Perpendicular to the ramp: \( F_{g,\perp} = F_g \cos(\theta) \)#### Calculation Steps:1. **Calculate the component of gravitational force parallel to the ramp**: \[ F_{g,\parallel} = m \cdot g \cdot \sin(\theta) = 48 \, \text{kg} \cdot 9.81 \, \text{m/s}^2 \cdot \sin(29.5^\circ) \] 2. **Calculate the component of gravitational force perpendicular to the ramp**: \[ F_{g,\

Name: ### Problem Statement: Motion of a Crate on an Inclined RampYou manag
Uploaded: 2024-03-20T06:57:57.000Z
Channel: Bartleby
Description: ### Problem Statement: Motion of a Crate on an Inclined RampYou managed to pull a heavy crate up a ramp on a truck. The crate has a mass of 48 kg. You were pulling with 464 N of force along the ramp while the ramp made an angle of θ = 29.5 degrees w