A child is pulling a red wagon full of toys (total mass is 8.35 kg). His pull is 34 N in magnitude and at 23 degrees above the horizontal. He pulls his wagon at a constant acceleration (could be positive or negative). The coefficient of friction between the wagon's wheels and the ground is 0.33. What is the wagon's acceleration?
A child is pulling a red wagon full of toys (total mass is 8.35 kg). His pull is 34 N in magnitude and at 23 degrees above the horizontal. He pulls his wagon at a constant acceleration (could be positive or negative). The coefficient of friction between the wagon's wheels and the ground is 0.33. What is the wagon's acceleration?
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:**Title: Calculating the Wagon's Acceleration**
**Problem Statement:**
A child is pulling a red wagon full of toys (total mass is 8.35 kg). His pull is 34 N in magnitude and at 23 degrees above the horizontal. He pulls his wagon at a constant acceleration (which could be positive or negative). The coefficient of friction between the wagon's wheels and the ground is 0.33. What is the wagon's acceleration?
**Given Data:**
- Total mass of the wagon: 8.35 kg
- Force exerted by the child: 34 N
- Angle of the pull: 23 degrees above the horizontal
- Coefficient of friction (μ): 0.33
**Objective:**
Determine the acceleration of the wagon.
**Explanation of Solution:**
1. **Resolve the Pulling Force:**
- The pulling force has two components:
- Horizontal component, \( F_{\text{horizontal}} = 34 \cos(23^\circ) \)
- Vertical component, \( F_{\text{vertical}} = 34 \sin(23^\circ) \)
2. **Calculate the Normal Force:**
- The normal force \( F_N \) can be determined by considering the gravitational force and the vertical component of the pulling force.
- The gravitational force is \( F_g = mg = 8.35 \times 9.8 \, \text{N} \)
- Thus, \( F_N = F_g - F_{\text{vertical}} \)
3. **Calculate the Frictional Force:**
- The frictional force \( F_f \) is given by \( F_f = \mu F_N \)
4. **Determine the Net Force:**
- The net force acting on the wagon in the horizontal direction, \( F_{\text{net}} \), is given by \( F_{\text{net}} = F_{\text{horizontal}} - F_f \)
5. **Calculate the Acceleration:**
- Using Newton's second law, the acceleration \( a \) of the wagon can be determined by \( F_{\text{net}} = ma \)
- Solve for \( a \) to find the wagon's acceleration.
**Note:**
When performing the calculations, ensure to keep the units consistent and use trigonometric values accurately. The final formula for acceleration (\( a \)) can be
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