A block is pressed against a vertical wall by a force F, as the drawing shows. This force can either push the block upward at a constant velocity or allow it to slide downward at a constant velocity. The magnitude of the force is different in the two cases, while the directional angle is the same. Kinetic friction exists between the block and the wall, and the coefficient of kinetic friction is 0.260. The weight of the block is 47.0 N, and the directional angle for the force is 0 = 48.0°. Determine the magnitude of when the block slides (a) up the wall and (b) down the wall. (a) P= (b) P= i i

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ISBN:9781305952300
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Chapter1: Units, Trigonometry. And Vectors
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**Title: Understanding Forces Acting on a Block Against a Vertical Wall**

**Introduction:**
In this exercise, we analyze a block being pressed against a vertical wall by a force \(\vec{F}\) as shown in the accompanying diagram.

**Diagram Explanation:**
The diagram illustrates a block pressed against a vertical wall. The force \(\vec{F}\) acts on the block at an angle \(\theta\) to the horizontal. This angle is given as 48.0°.

![Diagram of force acting on a block](block-diagram.png)

**Problem Statement:**
The force \(\vec{F}\) applied to the block can facilitate two scenarios:

1. The block moving upward at a constant velocity.
2. The block sliding downward at a constant velocity.

While the direction of force application angle \(\theta\) remains the same in both cases, the magnitudes of the forces differ. The coefficient of kinetic friction (\(\mu_k\)) between the block and the wall is 0.260, and the weight (W) of the block is 47.0 N.

**Objective:**
Determine the magnitude of the force \(\vec{F}\) for the following conditions:
(a) When the block slides up the wall.
(b) When the block slides down the wall.

**Given Data:**
- \( \mu_k = 0.260 \) (coefficient of kinetic friction)
- Weight \( W = 47.0 \) N
- Angle \( \theta = 48.0^\circ \)

**Questions:**
(a) Find the magnitude of the force \( \vec{F} \) when the block slides up the wall:

\[ (a) \quad P = \]

(b) Find the magnitude of the force \( \vec{F} \) when the block slides down the wall:

\[ (b) \quad P = \]

**Analyzing the Problem:**
To solve for \( \vec{F} \), consider the equilibrium conditions for the block in both the upward and downward motion scenarios. Utilize the frictional force equations, and ensure the balance of forces in both the vertical and horizontal directions. The magnitude of force \( \vec{F} \) in both cases depends on the interplay between gravitational force, kinetic friction, and the applied force vector’s components.

By accurately analyzing the given conditions and applying Newton’s laws, one can derive the precise magnitudes for
Transcribed Image Text:**Title: Understanding Forces Acting on a Block Against a Vertical Wall** **Introduction:** In this exercise, we analyze a block being pressed against a vertical wall by a force \(\vec{F}\) as shown in the accompanying diagram. **Diagram Explanation:** The diagram illustrates a block pressed against a vertical wall. The force \(\vec{F}\) acts on the block at an angle \(\theta\) to the horizontal. This angle is given as 48.0°. ![Diagram of force acting on a block](block-diagram.png) **Problem Statement:** The force \(\vec{F}\) applied to the block can facilitate two scenarios: 1. The block moving upward at a constant velocity. 2. The block sliding downward at a constant velocity. While the direction of force application angle \(\theta\) remains the same in both cases, the magnitudes of the forces differ. The coefficient of kinetic friction (\(\mu_k\)) between the block and the wall is 0.260, and the weight (W) of the block is 47.0 N. **Objective:** Determine the magnitude of the force \(\vec{F}\) for the following conditions: (a) When the block slides up the wall. (b) When the block slides down the wall. **Given Data:** - \( \mu_k = 0.260 \) (coefficient of kinetic friction) - Weight \( W = 47.0 \) N - Angle \( \theta = 48.0^\circ \) **Questions:** (a) Find the magnitude of the force \( \vec{F} \) when the block slides up the wall: \[ (a) \quad P = \] (b) Find the magnitude of the force \( \vec{F} \) when the block slides down the wall: \[ (b) \quad P = \] **Analyzing the Problem:** To solve for \( \vec{F} \), consider the equilibrium conditions for the block in both the upward and downward motion scenarios. Utilize the frictional force equations, and ensure the balance of forces in both the vertical and horizontal directions. The magnitude of force \( \vec{F} \) in both cases depends on the interplay between gravitational force, kinetic friction, and the applied force vector’s components. By accurately analyzing the given conditions and applying Newton’s laws, one can derive the precise magnitudes for
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