I need help in being able to detect a max heap You have to write a code which will help to determine whether a binary tree is a max heap. Thefollowing code is a sample implementation of a binary tree, you can use it as a sample example.Code should print whether the tree is a max heap or not.class Node {public:int data;Node* left;Node* right;Node(int data) {this->data data;left = NULL;right = NULL;}}};int main() {Node* root = new Node(10);root->left = new Node(9);root->right = new Node(8);root->left->left = new Node(7);root->left->right = new Node(6);root->right->left = new Node(5);root->right->right = new Node(4);root->left->left->left = new Node(3);root->left->left->right = new Node(2);root->left->right->left = new Node(1);

Algorithm: isMaxHeap(root)Input: root - The root of the binary treeOutput: true if the tree is a max…

You have to write a code which will help to determine whether a binary tree is a max heap. The following code is a sample implementation of a binary tree, you can use it as a sample example. Code should print whether the tree is a max heap or not.

You have to write a code which will help to determine whether a binary tree is a max heap. The following code is a sample implementation of a binary tree, you can use it as a sample example. Code should print whether the tree is a max heap or not.

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

I need help in being able to detect a max heap

You have to write a code which will help to determine whether a binary tree is a max heap. The
following code is a sample implementation of a binary tree, you can use it as a sample example.
Code should print whether the tree is a max heap or not.
class Node {
public:
int data;
Node* left;
Node* right;
Node(int data) {
this->data data;
left = NULL;
right = NULL;
}
}
};
int main() {
Node* root = new Node(10);
root->left = new Node(9);
root->right = new Node(8);
root->left->left = new Node(7);
root->left->right = new Node(6);
root->right->left = new Node(5);
root->right->right = new Node(4);
root->left->left->left = new Node(3);
root->left->left->right = new Node(2);
root->left->right->left = new Node(1);

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