### Example Problem on Determining Molarity#### Problem Statement:You dissolve 14 g of \( \text{Mg(NO}_3\text{)}_2 \) in water and dilute to 750 mL. What is the molarity of this solution?Show your work.### Solution:1. **Calculate the molar mass of \( \text{Mg(NO}_3\text{)}_2 \):** - Mg: 24.31 g/mol - N: 14.01 g/mol (2 atoms of N -> \( 2 \times 14.01 \) = 28.02 g/mol) - O: 16.00 g/mol (6 atoms of O -> \( 6 \times 16.00 \) = 96.00 g/mol) Molar Mass of \( \text{Mg(NO}_3\text{)}_2 \) = 24.31 + 28.02 + 96.00 = 148.33 g/mol2. **Calculate moles of \( \text{Mg(NO}_3\text{)}_2 \):** \[ \text{Moles of } \text{Mg(NO}_3\text{)}_2 = \frac{\text{mass}}{\text{molar mass}} = \frac{14 \, \text{g}}{148.33 \, \text{g/mol}} = 0.0944 \, \text{moles} \]3. **Convert 750 mL to liters:** \[ 750 \, \text{mL} = 0.750 \, \text{L} \]4. **Calculate molarity (M):** \[ \text{Molarity} = \frac{\text{moles of solute}}{\text{liters of solution}} = \frac{0.0944 \, \text{moles}}{0.750 \, \text{L}} = 0.126 \, \text{M} \]### Answer:The molarity of the solution is 0.126 M.

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Answered: You dissolve 14 g of gv03/2 in water…

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Chemistry

You dissolve 14 g of gv03/2 in water and dilute to 750 mL. What is the molarity of this solution? Show your work.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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