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A student needs 50.0 mL of 5.74×10 -4 M FD&C Blue Dye No. 1 solution. If the student has 2.00 mM FD&C Blue Dye No. 1 stock solution to work with, how much of the 2.00 mM solution should be added to the 50.0 mL volumetric flask? Hint, 2.00 mM is 0.00200 M.     14.35 mL     0.06971 mL     3.485 mL     12.85 mL     6.971 mL

A student needs 50.0 mL of 5.74×10 -4 M FD&C Blue Dye No. 1 solution. If the student has 2.00 mM FD&C Blue Dye No. 1 stock solution to work with, how much of the 2.00 mM solution should be added to the 50.0 mL volumetric flask? Hint, 2.00 mM is 0.00200 M.     14.35 mL     0.06971 mL     3.485 mL     12.85 mL     6.971 mL

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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  1. A student needs 50.0 mL of 5.74×10 -4 M FD&C Blue Dye No. 1 solution. If the student has 2.00 mM FD&C Blue Dye No. 1 stock solution to work with, how much of the 2.00 mM solution should be added to the 50.0 mL volumetric flask? Hint, 2.00 mM is 0.00200 M.
       
    14.35 mL
       
    0.06971 mL
       
    3.485 mL
       
    12.85 mL
       
    6.971 mL
     
Expert Solution
Step 1

Given: Concentration of stock solution = 2.00 mM = 0.002 M                       (Since 1 M = 1000 mM)

Final volume of solution = 50.0 mL.

And concentration of final solution = 0.000574 M

 

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