In the lab, you used 2.0 mM FD&C Red Dye No. 40 solution. How much solid dye, molar mass 496.42 g/mol, should be dissolved to make 6.30 liters of 6.39 mM FD&C Red Dye No. 40 solution? Hint, 2.0 mM is 0.0020 M.     81.09 g     0.05004 g     0.8477 g     19.98 g     40.26 g

Q: In the lab, a student makes a solution of CaCl 2 by dissolving 9.0 grams of solid in 425 mL of…

A: We have given that  Mass of CaCl2 = 9 gram  Volume of solution = 425ml = 0.425L  We know that…

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Q: In the lab, you used 2.0 mM FD&C Red Dye No. 40 solution. How much solid dye, molar mass 496.42…

A: Given, molar mass of solid dye = 496.42 gmol volume of red-dye-40 = 1.8 L concentration of…

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A: Molarity (M) The equation to calculate molarity is ; M=given massmolar mass×volume of solution(L)

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A: first find the amount of Na2SO4 then find Fraction composition of Na in  Na2SO4 Then Multiply…

Q: In the lab, you used 2.0 mM FD&C Red Dye No. 40 solution. How much solid dye, molar mass 496.42…

A: Given: The molar mass of solid dye, (M) = 496.42 g/mol. The volume of the resulting solution, (V) =…

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Q: In the lab, you used 2.0 mM FD&C Yellow Dye No. 6 solution. How much solid dye, molar mass 452.36…

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Q: Part 1: 8.132g of CaCl2 are dissolved in 950.0 mL of water. Calculate the molarity of the CaCl2…

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Q: In the lab, you used 2.0 mM FD&C Red Dye No. 40 solution. How much solid dye, molar mass 496.42…

A: Given: Concentration of FD&C Red Dye No. 40 solution = 2.39 mM = 0.00239 M…

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