If you have 155 mL solution of a 0.762 M FeCb solution, how many g FeCb are contained in this sample? 155 ml solution motFect x 0.762 STARTING AMOUNT molFeC. 155 ml solution 0.762 mol FeCh x- 1 mol FeCl ADD FACTOR DELETE ANSWER RESET *( ) 1000 0.1 124 4.92 1.92 0.203 162.2 55.85 12.6 35.45 100 25.1 7.28 x 10 6.60 1 0.762 155 0.118 19.2 0.01 mol FeCt g FeCl/mol FeCl L solution g FeCh g CF M FeCb g Fe* ml solution mol FeCl:/L solution

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# Calculating Mass of FeCl₃ in a Solution

## Question
If you have a 155 mL solution of a 0.762 M FeCl₃ solution, how many grams of FeCl₃ are contained in this sample?

## Setup
- **Starting Amount:** 0.762 mol/L FeCl₃
- **Volume of Solution:** 155 mL

## Calculation Steps
1. **Convert Volume to Liters:** 
   - Given 155 mL solution. This is converted to liters as \( \frac{155}{1000} = 0.155 \) L.

2. **Determine the moles of FeCl₃:**
   - Use the molarity equation: 
     - \( \text{Moles of FeCl₃} = \text{Molarity} \times \text{Volume in L} \)
     - \( \text{Moles of FeCl₃} = 0.762 \, \text{mol/L} \times 0.155 \, \text{L} = 0.11811 \, \text{mol} \)

3. **Convert moles to grams:**
   - **Molar Mass of FeCl₃:** (commonly calculated as 162.2 g/mol; confirm with specific work if precise).
   - **Formula:** \( \text{grams} = \text{moles} \times \text{molar mass} \)
   - **Calculation:** \( 0.11811 \, \text{mol} \times 162.2 \, \text{g/mol} = 19.15 \, \text{g} \)

## Tool Interface
- **Control Buttons:**
  - **Add Factor:** Allows you to add multiplication or division factors.
  - **Delete:** Use to remove steps.
  - **Answer:** To display the final outcome.
  - **Reset:** Clears the current calculation to start fresh.

- **Conversion Options:**
  - Available units for conversion (grams, moles, liters, etc.).
  - Specific constants and values provided for quick calculations, including molar masses.
Transcribed Image Text:# Calculating Mass of FeCl₃ in a Solution ## Question If you have a 155 mL solution of a 0.762 M FeCl₃ solution, how many grams of FeCl₃ are contained in this sample? ## Setup - **Starting Amount:** 0.762 mol/L FeCl₃ - **Volume of Solution:** 155 mL ## Calculation Steps 1. **Convert Volume to Liters:** - Given 155 mL solution. This is converted to liters as \( \frac{155}{1000} = 0.155 \) L. 2. **Determine the moles of FeCl₃:** - Use the molarity equation: - \( \text{Moles of FeCl₃} = \text{Molarity} \times \text{Volume in L} \) - \( \text{Moles of FeCl₃} = 0.762 \, \text{mol/L} \times 0.155 \, \text{L} = 0.11811 \, \text{mol} \) 3. **Convert moles to grams:** - **Molar Mass of FeCl₃:** (commonly calculated as 162.2 g/mol; confirm with specific work if precise). - **Formula:** \( \text{grams} = \text{moles} \times \text{molar mass} \) - **Calculation:** \( 0.11811 \, \text{mol} \times 162.2 \, \text{g/mol} = 19.15 \, \text{g} \) ## Tool Interface - **Control Buttons:** - **Add Factor:** Allows you to add multiplication or division factors. - **Delete:** Use to remove steps. - **Answer:** To display the final outcome. - **Reset:** Clears the current calculation to start fresh. - **Conversion Options:** - Available units for conversion (grams, moles, liters, etc.). - Specific constants and values provided for quick calculations, including molar masses.
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