You are interested in whether there is any association between gender and academic major. Questioning 75 students, you obtain the following results: Observed FrequenciesMajorFemaleMaleTotalBusiness101222Science91120Liberal Arts91019Other7714Total354075(1 point) State your null and alternative hypotheses.(1 point) How many degrees of freedom are involved?(4 points) Calculate expected frequencies for each cell, and insert the values in the table provided below.Expected FrequenciesMajorFemaleMaleTotalBusiness 22Science 20Liberal Arts 19Other 14Total354075 (4 points) Calculate the square of Observed Frequency (fo) minus Expected Frequency (fe). Then divide by Expected Frequency (fe).(fo – fe)2 / feMajorFemaleMaleTotalBusiness 22Science 20Liberal Arts 19Other 14Total354075 (1 points) What is the calculated value of ?(1 point) Assuming the .05 level of significance, do you reject, or fail to reject, the null hypothesis?

Name: You are interested in whether there is any association between gender
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Description: You are interested in whether there is any association between gender and academic major. Questioning 75 students, you obtain the following results: Observed FrequenciesMajorFemaleMaleTotalBusiness101222Science91120Liberal Arts91019Other7714Total3540

================================================== 1. H0: There is no association between gender and academic major (Null) H1: There is an association between gender and academic major (Alternative) ==================================================== 2. dof = (#rows -1)(# column -1) = (4-1)(2-1) = 3 ====================================================== 3. Expected value of a cell (fe) = Row sub total ×column sub totalGrand total Example (fe (Business , female) ) = 22×3575 = 10.27 Similarly for others Female Male Total Business 10.27 11.73 22 Science 9.33 10.67 20 Liberal Arts 8.87 10.13 19 Other 6.53 7.47 14 Total 35 40 75 (fo-fe)2fe Female Male Total Business 0.0069 0.0061 0.0130 Science 0.0119 0.0104 0.0223 Liberal Arts 0.0020 0.0018 0.0038 Other 0.0333 0.0292 0.0625 Total 0.0542 0.0474 0.1016 ∑(fo-fe)2fe=0.1016 (Calculated value ) 2. P-value = CHISQ.DIST.RT(0.1016,3) ----Excel function = 0.9916 > 0.05 fail to reject the null hypothesis

Answered: You are interested in whether there is…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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You are interested in whether there is any association between gender and academic major. Questioning 75 students, you obtain the following results:

Observed Frequencies

Major	Female	Male	Total
Business	10	12	22
Science	9	11	20
Liberal Arts	9	10	19
Other	7	7	14
Total	35	40	75

(1 point) State your null and alternative hypotheses.
(1 point) How many degrees of freedom are involved?
(4 points) Calculate expected frequencies for each cell, and insert the values in the table provided below.

Expected Frequencies

Major	Female	Male	Total
Business			22
Science			20
Liberal Arts			19
Other			14
Total	35	40	75

(4 points) Calculate the square of Observed Frequency (f_o) minus Expected Frequency (f_e). Then divide by Expected Frequency (f_e).

(f_o – f_e)² / f_e

Major	Female	Male	Total
Business			22
Science			20
Liberal Arts			19
Other			14
Total	35	40	75

(1 points) What is the calculated value of ?
(1 point) Assuming the .05 level of significance, do you reject, or fail to reject, the null hypothesis?

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