You are given a mixture of CuCO3 and CuO. You place the mixture in a crucible and heat it to decompose the CuCO3 into CO2 gas and CuO. You made sure that the CuCO3 had completely decomposed by constantly heating it, cooling it, and weighing it until the mass remains the same. Using the data below from the experiment, calculate the % CuCO3 in the original sample. Mass of empty crucible: 22.19 g Mass of crucible + sample before heating: 23.193 g Mass of crucible + sample at constant mass: 22.851 g
You are given a mixture of CuCO3 and CuO. You place the mixture in a crucible and heat it to decompose the CuCO3 into CO2 gas and CuO. You made sure that the CuCO3 had completely decomposed by constantly heating it, cooling it, and weighing it until the mass remains the same.
Using the data below from the experiment, calculate the % CuCO3 in the original sample.
Mass of empty crucible: 22.19 g
Mass of crucible + sample before heating: 23.193 g
Mass of crucible + sample at constant mass: 22.851 g
PLease show and create one solution map: i made this solution map, is it correct? 1.561g CO2 x (1mol CO2/44.01g CO2) x (1mol CrCO3/1mol CO2) x (112.01g CrCO3/1mol CrCO3)= 3.973g CrCO3
than, (3.973/25.422) x 100% = 15.63%
2.) A 12.622 g sample of a compound that contains sulfur is analyzed by precipitating all the sulfur as BaSO4. If 11.957 g of BaSO4 are obtained in the analysis, what is the percentage of sulfur in the original compound?
(Need help with this one too)
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