When you are presented with additional details, it can sometimes be a little more difficult to determine which information is necessary and how molarity should be applied. Using both a solution map and dimensional analysis can help clarify which information and conversion factors are necessary to determine the desired value. The following dimensional analysis setup could be used to determine the theoretical mass of AIBr3 (s) (molecular mass = 266.69 g/mol ) produced based on reacting 45.8 g of a 0.074 mol/L solution of Br2 (1) (density = 1046 g/L ) with excess Al(s) as described in the following equation: 3B12 (1) + 2A1(s) → 2AIB13 (s) Complete the dimensional analysis for calculating the mass of the product by placing the values of each conversion factor according to whether they should appear in the numerator or denominator when calculating the mass of AlBr3 (s) produced from a sample of Br2 (1). Drag the appropriate values to their respective targets. • View Available Hint(s) Reset Help 1L solution 45.8 g Br2(1) 1046 g Br2(1) 3 mol Br2(1) 2 mol AlBr3(s) 1 mol AlBr3(s) 266.69 g AlBr3(s) 1L solution 0.074 mol Br2(1) Group 1 Group 2 Group 4 Group 3 Group 1 Group 1 Group 2 Group 4 Group 3

Chemistry
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When you are presented with additional details, it can sometimes be a little more difficult to determine which information is necessary and how molarity should be applied. Using both a solution map and
dimensional analysis can help clarify which information and conversion factors are necessary to determine the desired value.
The following dimensional analysis setup could be used to determine the theoretical mass of AlBr3 (s) (molecular mass = 266.69 g/mol ) produced based on reacting 45.8 g of a 0.074 mol/L solution of
Br2 (1) (density = 1046 g/L ) with excess Al(s) as described in the following equation:
3B12 (1) + 2Al(s) → 2AIB13 (s)
Complete the dimensional analysis for calculating the mass of the product by placing the values of each conversion factor according to whether they should appear in the numerator or denominator when
calculating the mass of AlBr3 (s) produced from a sample of Br2 (1).
Drag the appropriate values to their respective targets.
• View Available Hint(s)
Reset
Help
1 L solution
45.8 g Br2(1)
1046 g Br2(1)
3 mol Br2(1)
2 mol AlBr3(s)
1 mol AlBr3(s)
266.69 g AlBr3 (s)
1 L solution
0.074 mol Br2(1)
Group 1
Group 2
Group 4
Group 3
Group 1
Group 1
Group 2
Group 4
Group 3
Transcribed Image Text:When you are presented with additional details, it can sometimes be a little more difficult to determine which information is necessary and how molarity should be applied. Using both a solution map and dimensional analysis can help clarify which information and conversion factors are necessary to determine the desired value. The following dimensional analysis setup could be used to determine the theoretical mass of AlBr3 (s) (molecular mass = 266.69 g/mol ) produced based on reacting 45.8 g of a 0.074 mol/L solution of Br2 (1) (density = 1046 g/L ) with excess Al(s) as described in the following equation: 3B12 (1) + 2Al(s) → 2AIB13 (s) Complete the dimensional analysis for calculating the mass of the product by placing the values of each conversion factor according to whether they should appear in the numerator or denominator when calculating the mass of AlBr3 (s) produced from a sample of Br2 (1). Drag the appropriate values to their respective targets. • View Available Hint(s) Reset Help 1 L solution 45.8 g Br2(1) 1046 g Br2(1) 3 mol Br2(1) 2 mol AlBr3(s) 1 mol AlBr3(s) 266.69 g AlBr3 (s) 1 L solution 0.074 mol Br2(1) Group 1 Group 2 Group 4 Group 3 Group 1 Group 1 Group 2 Group 4 Group 3
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