You are designing a suspension linkage rod for a new sports car. It will be 12 inches long and fixed-pinned at the ends. The rod must support an axial load of 10 kips (compression). Design the smallest solid circular aluminum rod (diameter rounded to the nearest 0.1 inch), to prevent both buckling and yield failure. Use a factor of safety of 3.0 with respect to both buckling and yield. Assume Aluminum E = 10000 ksi, o, = 40 ksi. %3D [Formula: Axial Loading: Normal Stress o = (P)/(A); Axial Deformatipn 8 = (P)(L/(AE); Buckling Capacity: Per = (r')(EI)/(k*L)’, where 'k' is effective length factor] %3D L= 12 in Fixed-Pinned

Structural Analysis
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ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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You are designing a suspension linkage rod for a new sports car. It will be 12 inches long and
fixed-pinned at the ends. The rod must support an axial load of 10 kips (compression). Design
the smallest solid circular aluminum rod (diameter rounded to the nearest 0.1 inch), to prevent
both buckling and yield failure. Use a factor of safety of 3.0 with respect to both buckling and
yield. Assume Aluminum E = 10000 ksi, o, = 40 ksi.
%3D
[Formula: Axial Loading: Normal Stress o = (P)/(A); Axial Deformatipn 8 = (P)(L/(AE);
Buckling Capacity: Per = (r')(EI)/(k*L)’, where 'k' is effective length factor]
%3D
L= 12 in
Fixed-Pinned
Transcribed Image Text:You are designing a suspension linkage rod for a new sports car. It will be 12 inches long and fixed-pinned at the ends. The rod must support an axial load of 10 kips (compression). Design the smallest solid circular aluminum rod (diameter rounded to the nearest 0.1 inch), to prevent both buckling and yield failure. Use a factor of safety of 3.0 with respect to both buckling and yield. Assume Aluminum E = 10000 ksi, o, = 40 ksi. %3D [Formula: Axial Loading: Normal Stress o = (P)/(A); Axial Deformatipn 8 = (P)(L/(AE); Buckling Capacity: Per = (r')(EI)/(k*L)’, where 'k' is effective length factor] %3D L= 12 in Fixed-Pinned
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