Problem 2: The aluminum W 310 x 202 (wide flange) column is subjected to an eccentric axial load P as shown. The maximum compressive stress in the column is given by the so-called secant formula: where O max=σ ec sec [1+(公園)] -P/A-average stress A=25800 mm² = cross-sectional area of the column e=85 mm eccentricity of the load c-170 min-half depth of the column r=142 mm radius of gyration of the cross section L= 7100 mm = length of the column E=71 x 10° Pa=modulus of elasticity Determine the maximum load P that the column can carry if the maximum stress is not to exceed 120 x 106 Pa. Terminate the computation when Σa < 0.0005%

Steel Design (Activate Learning with these NEW titles from Engineering!)
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Author:Segui, William T.
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Chapter1: Introduction
Section: Chapter Questions
Problem 1.5.6P: The data in Table 1.5.3 were obtained from a tensile test of a metal specimen with a rectangular...
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Problem 2: The aluminum W 310 x 202 (wide flange) column is subjected to an eccentric
axial load P as shown. The maximum compressive stress in the column is given by
the so-called secant formula:
where
O max=σ
ec
sec
[1+(公園)]
-P/A-average stress
A=25800 mm² = cross-sectional area of the column
e=85 mm eccentricity of the load
c-170 min-half depth of the column
r=142 mm radius of gyration of the cross section
L= 7100 mm = length of the column
E=71 x 10° Pa=modulus of elasticity
Determine the maximum load P that the column can carry if the maximum stress is
not to exceed 120 x 106 Pa. Terminate the computation when Σa < 0.0005%
Transcribed Image Text:Problem 2: The aluminum W 310 x 202 (wide flange) column is subjected to an eccentric axial load P as shown. The maximum compressive stress in the column is given by the so-called secant formula: where O max=σ ec sec [1+(公園)] -P/A-average stress A=25800 mm² = cross-sectional area of the column e=85 mm eccentricity of the load c-170 min-half depth of the column r=142 mm radius of gyration of the cross section L= 7100 mm = length of the column E=71 x 10° Pa=modulus of elasticity Determine the maximum load P that the column can carry if the maximum stress is not to exceed 120 x 106 Pa. Terminate the computation when Σa < 0.0005%
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