You are conducting a study to see if the accuracy rate for fingerprint identification is significantly less than 0.72. You use a significance level of α=0.02 H0:p=0.72 H1:p<0.72You obtain a sample of size n=291n=291 in which there are 192 successes.What is the test statistic for this sample? (Report answer accurate to three decimal places.)test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.)p-value = The p-value is...less than (or equal to) ααgreater than ααThis test statistic leads to a decision to...reject the nullaccept the nullfail to reject the nullAs such, the final conclusion is that...There is sufficient evidence to warrant rejection of the claim that the accuracy rate for fingerprint identification is less than 0.72.There is not sufficient evidence to warrant rejection of the claim that the accuracy rate for fingerprint identification is less than 0.72.The sample data support the claim that the accuracy rate for fingerprint identification is less than 0.72.There is not sufficient sample evidence to support the claim that the accuracy rate for fingerprint identification is less than 0.72.

Name: You are conducting a study to see if the accuracy rate for fingerprint
Uploaded: 2024-03-20T07:07:12.000Z
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Description: You are conducting a study to see if the accuracy rate for fingerprint identification is significantly less than 0.72. You use a significance level of α=0.02 H0:p=0.72 H1:p<0.72You obtain a sample of size n=291n=291 in which there are 192 s

The claim of the hypotheses test is that, accuracy rate for fingerprint identification is significantly less than p=0.72. The size of the sample is n = 291 and the number of successes is x =192. The sample proportion is, p^=xn=192291=0.6598 The value of test statistic is, z=p^-pp1-pn=0.6598-0.720.721-0.72291=-0.06020.2016291=-0.06020.00069=-0.06020.0263=-2.289 Thus, the test statistic for this sample is -2.289.The hypothesis is left tail. The p-value for left tailed test is p-value=Pz<-2.289 The probability of z less than -2.289 can be obtained using the excel formula “=NORM.S.DIST(-2.289,TRUE)”. The probability value is 0.0110. Thus, the required p-value is 0.0110. Decision rule: If p-value≤α, then reject the null hypothesis. Otherwise, do not reject the null hypothesis. Conclusion: The p-value (0.0110) is less than the level of significance (0.02). Based on decision rule, reject the null hypothesis. Thus, there is not sufficient evidence to warrant rejection of the claim that the accuracy rate for fingerprint identification is less than 0.72.

Answered: You are conducting a study to see if…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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You are conducting a study to see if the accuracy rate for fingerprint identification is significantly less than 0.72. You use a significance level of α=0.02

H0:p=0.72
H1:p<0.72

You obtain a sample of size n=291n=291 in which there are 192 successes.

What is the test statistic for this sample? (Report answer accurate to three decimal places.)
test statistic =

What is the p-value for this sample? (Report answer accurate to four decimal places.)
p-value =

The p-value is...

less than (or equal to) αα
greater than αα

This test statistic leads to a decision to...

reject the null
accept the null
fail to reject the null

As such, the final conclusion is that...

There is sufficient evidence to warrant rejection of the claim that the accuracy rate for fingerprint identification is less than 0.72.
There is not sufficient evidence to warrant rejection of the claim that the accuracy rate for fingerprint identification is less than 0.72.
The sample data support the claim that the accuracy rate for fingerprint identification is less than 0.72.
There is not sufficient sample evidence to support the claim that the accuracy rate for fingerprint identification is less than 0.72.

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