You are a scout doing a merit badge on fire starting and have a magnifying glass with a focal length 9.2 cm. The Sun is 150 million km away. How close to the tinder (fire starter) should you hold the magnifying glass to have the best chance of starting a fire? (You want to concentrate the sunlight).
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- What is the focal length of the lens in your eye when you can focus on an object at your near point? Assume that the distance from your lens to the back of your eye is 2.0 cm, that your near point is 21 cm in front of your lens, and that the liquid behind the lens has n=1.00 just like the air in front of your lens. (a) 1.8 cm (b) 18 cm (c) 2.1 cm (d) 21 cm (e) None of the above.A person focusses on a page of text held 40.0 cm away from their eye. A character is 0.3 cm tall. Calculate the height of the character on the retina, and the focal length of the lens. You can assume that the eyeball is 2.0 cm in diameter. Optics of the Human Eye Overlay Eye Anatomy Retina Fovea centralis Optic Nerve Central retinal v. Superior rectus m Ora serrata Cillary body Vitreous Bode Lens Inferior rectus m Posterior chamber Anterior Chamber Comea Zonules Sclera Object Far Near Focus Normal Vision Near Sighted Object Position Far Sighted Near Needs Bifocals FarIt is your first day at work as a summer intern at an optics company. Your supervisor hands you a diverging lens and asks you to measure its focal length. You know that with a converging lens, you can measure the focal length by placing an object a distance ss to the left of the lens, far enough from the lens for the image to be real, and viewing the image on a screen that is to the right of the lens. By adjusting the position of the screen until the image is in sharp focus, you can determine the image distance s′s′ and then use the equation 1s+1s′=1f1s+1s′=1f, to calculate the focal length ff of the lens. But this procedure won't work with a diverging lens−−by itself, a diverging lens produces only virtual images, which can't be projected onto a screen. Therefore, to determine the focal length of a diverging lens, you do the following: First you take a converging lens and measure that, for an object 20.0 cmcm to the left of the lens, the image is 29.7 cmcm to the right of the lens.…
- You need to use a 23- cm -focal-length lens to produce an inverted image one third the height of an object. At what distance from the object should the lens be placed? Express your answer with the appropriate units.You place an object 24.8 cm in front of a diverging lens which has a focal length with a magnitude of 11.0 cm. Determine how far in front of the lens the object should be placed in order to produce an image that is reduced by a factor of 2.95.A small telescope has a concave mirror with a 2.6 m radius of curvature for its objective. Its eyepiece is a 3.4 cm focal length lens. Part (b) What angle (in degrees) is subtended by a 25,000 km diameter sunspot? Assume the sun is 1.50 × 108 km away. Part (c) What is the image angular size (in degrees) in this telescope?
- An object is 21 cm in front of a diverging lens that has a focal length of -9.6 cm. How far in front of the lens should the object be placed so that the size of its image is reduced by a factor of 2.6?3. A cell phone has a fixed focal length lens of f = 3.85 mm = 0.00385 m and can take pictures over a range of distances from S. = 0.5 m to S,= infinity. Over what range of distances (S₁) does the lens in the cellphone have to move to focus an image at these two extremes in object distance?You are a marine biologist and want to pull a star fish out of a tank of water for testing. Looking from the top of the tank, where is the actual starfish compared to the image of the starfish that you see from the surface? Explain.