A 2.37 cm tall object is placed 20.7 cm away from the flat side of a plano-convex lens that has a focal length of 11.2 cm. Using the standard sign convention, what will be the height of the image (in cm)? Your Answer:
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A: From thin lens formula:
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A: Index of refraction, μ = 1.33Radius of curvature, R1 = -0.521 m (front) Radius of curvature, R2 =…
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A: Focal length: the distance between a mirror's or lens's focus and its centre
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A: The correct option is (c). i.e 45cm
Q: what is the focal foc
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A: Given:- fmirror = 12 cm flens = 10 cm
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A: given that for convex lens f= 13.6 cm radius R1 = R2 = 10.9 cm object…
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Q: How far from the lens is the object located?
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Q: lens that is convex on both sides is formed from a piece of plastic with an index of refraction of…
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Q: A lens that is constructed from a glass, whose index of refraction is 3, has a focal length of 22…
A: Given data: Index of refraction of first lens (μ1) = 3 Focal length of first lens (f1) = 22 cm Focal…
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Q: The figure shows an object and its image formed by a thin lens. Assume that d1 = 0.552 m, d2 = 0.398…
A: Object distance (u)= d1=0.552 m Image distance (v)=
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A: The magnification of the lens is given by The thin lens formula is given by
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Q: You have a lens whose focal length is −6.11 cm.−6.11 cm. You place an object on the axis of the lens…
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Q: An object of height 7.91cm is placed 40 cm from a converging lens of focal length 11.1 cm. How big…
A: Givenf=11.1 cmu=-40 cmho=7.91 cm
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A: Given A compound lens system consists of two converging lenses position of lense-1: x=−20.0 cm focal…
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Q: An object of height 10.0 cm is placed 20.0 cm away from a converging lens. The image is 30.0 cm…
A: Given image heigh hi= 30 cm object height ho=10 cm object distance u=- 20 cm We know lens…
Q: An image of the moon is focused onto a screen using a converging lens of focal length f= 35.3 cm.…
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- Please AsapYou place an object 21.2 cm in front of a diverging lens which has a focal length with a magnitude of 12.2 cm. Determine how far in front of the lens the object should be placed in order to produce an image that is reduced by a factor of 2.70.cmA system of two converging lenses forms an image of an arrow as shown. The first lens is located at x = 0 and has a focal length of f₁ = 8.8 cm. The second lens is located at x = x2 = 58.13 cm and has a focal length of f2 = 21 cm. The tip of the object arrow is located at (x,y) = (xo,Y)= (-12.3 cm, 6.9 cm). AY (X,Y) 1) What is x₁, the x-coordinate of image of the arrow formed by the first lens? cm Submit 2) What is y₁, the y-coordinate of the image of the tip of the arrow formed by the first lens? cm Submit Virtual and Inverted Virtual and Upright Submit X₂ cm Submit X 3) What is x3, the x co-ordinate of image of the arrow formed by the two lens system? cm Submit 5) What is the nature of the final image relative to the object? Real and Inverted Real and Upright ++++ 4) What is y3, the y-coordinate of the image of the tip of the arrow formed by the two lens system? + 6) Which of the following changes to the locations of the lenses would result in a virtual and inverted image of the…
- Consider a converging lens with focal length 8.94 cm. The distance between an object and a real image of the object created by the lens is 41.5 cm. Find the distance between the object and the lens if the lens is closer to the object than it is to the image. Answer in cm.10. A 1.1 cm tall object is placed 5 cm away from a mirror with focal length 16 cm. Calculate the height of the image. (Give your answer in centimeters but don't include the units.) MacBook D00 F2 F3 F4 F5 F6 F7 F8 @ & 4 5 6 7 8 W T Y K.An object is placed to the left of a lens, and a real image is formed to the right of the lens. The image is inverted relative to the object and is one-half the size of the object. The distance between the object and the image is 73.0 cm. (a) How far from the lens is the object? (b) What is the focal length of the lens? (a) do = (b) f=
- An object is placed 36cm to the left of a converging lens. The resulting image is five times the size of the object and projected onto a screen. What is the focal length of this lens?You place an object 21.4 cm in front of a diverging lens which has a focal length with a magnitude of 11.8 cm. Determine how far in front of the lens the object should be placed in order to produce an image that is reduced by a factor of 3.35. cm Additional MaterialsContact lenses are placed right on the eyeball, so the distance from the eye to an object (or image) is the same as the distance from the lens to that object (or image). A certain person can see distant objects well, but his near point is 46.0cm from his eyes instead of the usual 25.0cm .If the correcting lenses will be contact lenses, what focal length lens is needed ?
- The object is located at a distance of 20 cm from the lens, which forms upright image double of the size of the object. What is the focal distance of the lens? O- 5 cm O +0.4 m 10 cm O +20 cm O-0.2 m O-40 cmA system of two lenses forms an image of an arrow at x = x3 = 57.4 cm. The first lens is a diverging lens located at x = 0 and has a focal length of magnitude f₁ = 11.5 cm. The second lens is located at x = x₂ = 25.4 cm and has an unknown focal length. The tip of the object arrow is located at (x,y) = (xo, Yo) = (-36 cm, 20.6 cm). (x,y) 1) What is x₁, the x-coordinate of image of the arrow formed by the first lens? cm Submit 2) What is y₁, the y-coordinate of the image of the tip of the arrow formed by the first lens? cm Submit X₂ Real and Inverted Real and Upright Virtual and Inverted Virtual and Upright cm Submit (+) 3) What is f2, the focal length of the second lens. If the lens is a converging lens, f2 is positive. If the lens is a diverging lens, f2 is negative. cm Submit + 4) What is y3, the y-coordinate of the image of the tip of the arrow formed by the two lens system? (+ 5) The positions of the two lenses are now interchnaged (i.e., the second lens is moved to x = 0 and the…8. On one side of a converging lens of focal length 59.1 cm, you position an object of height 3.02 cm somewhere along the principal axis. The resultant image has a height of 15.10 cm. How far from the lens is the object located? 70.9 cm 28.4 cm 92.2 cm 42.5 cm