Y3/ In chemistry experiment seven students oblained the followng percentage of dhloride in asample of pure Sodium chloride : 60.65 , 60. 68 , 60.70 60.6o , 60.64 60.65 and 6o.67 . Find Hhe Average deviation of Hhe percentage of chloride:
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- For healthy young women average level of calcium in blood is 9.5 mg per deciliter with the typical standard deviation of 0.4 mg/dl. In a rurah hospital in Guatemala for 160 healthy women on early stages of pregnancy blood calcium level was measured; the average was 9.57 mg/dl. Does the average level differ from 9.5? Calculate the p-value, round it up to 4 decimal places.The histogram of the number of hours of sleep Stat 100 students reported getting each night roughly follows the normal curve with an average of 7.0 hours and a SD of 1.2 hours. a. Approximately 68% of the students sleep between hours and hot (Put the smaller number first) 提交答案|Tries 0/5 b. Approximately 95% of the students sleep between hours and hours. (Put the smaller number first) 提交答案| Tries 0/5 c. If a student sleeps 5.2 hours per night what percent of the people sleep more than her? Do the problem in steps: I. First, find the Z score = 提交答案|Tries 0/3 ii. Now, move the red vertical line on the following graph to the correct Z score by clicking and dragging the mouse. If you are using a touch screen, touch and then slide the region around the vertical line 1.00 Shade the region representing the percent of people who sleep more than her: Shade the region under the normal curve to the O left of the red vertical line O right of the red vertical lineThe one in the yellow is the previous tab.
- Overproduction of uric acid in the body can be an indication of cell breakdown. This may be an advance indication of illness such as gout, leukemia, or lymphoma.+ Over a period months, an adult male patient has taken five blood tests for uric acid. The mean concentration was x = 5.34 mg/dl. The distribution of uric acid in healthy adult males can be assumed to be normal, with σ = 1.83 mg/dl. (a) Find a 95% confidence interval for the population mean concentration of uric acid in this patient's blood. What is the margin of error? (Round your answers to two decimal places.) lower limit upper limit margin of error (b) What conditions are necessary for your calculations? (Select all that apply.) Oo is unknown O uniform distribution of uric acid F σ is known O normal distribution of uric acid On is large (c) Interpret your results in the context of this problem. O The probability that this interval contains the true average uric acid level for this patient is 0.05. O The probability that…Pulse rates of adult men are approximately normal with a mean of 70 and a standard deviation of 8. Which choice correctly describes how to find the proportion of men that have a pulse rate greater than 78? (a) Find the area to the right of z = -1 under a standard normal curve. (b) Find the area to the right of z=1 under a standard normal curve. (c) Find the area to the left of z = 1 under a standard normal curve. (d) Find the area between z=-1 and z=1 under a standard normal curve. (e) None of the aboveA normal distribution has a mean of μ = 50 and a standard deviation of σ =12. Find the proportion of the distribution located in the tail for X = 53.
- lustration 19.33. An examination was given to 50 students at College A and to 60 students at Collage B. At A, the mean grade was 75 with S.D.=9. At B, the mean was 79 with SD=7. Is there a significant difference in the performance at the two Colleges at 5% level of significance?Find the value of za/2 when 1- a = .98. Explain your answer by using the standard normal curve.= 222 mg/dLi and Total cholesterol levels for middle aged men (aged 55 – 64) follow approximately a normal distribution with mean, µ standard deviation, o = 37 mg/dLi. Those with a total cholesterol of 240 mg/dLi or higher have "high" cholesterol (and have twice the risk of coronary heart disease as someone with a total cholesterol less than 200 mg/dLi) Find the Z-score (standard score) for an observation of 290 mg/dl.
- Newspaper Reading Times A survey taken several years ago found that the average time a person spent reading the local daily newspaper was 10.8 minutes. The standard deviation of the population was 3 minutes. To see whether the average time had changed since the newspaper's format was revised, the newspaper editor surveyed 40 individuals. The average time that the 40 people spent reading the paper was 12.4 minutes. At α=0.10 , is there a change in the average time an individual spends reading the newspaper? Find the 90% confidence interval of the mean. (a) State the hypothesis and identify the claim with the correct hypothesis. :H0 ▼(Choose one) :H1 ▼(Choose one) This hypothesis test is a ▼(Choose one) test. (b)Find the critical value(s). Round the answer to 2 decimal places, if necessary. Critical values: (c)Compute the test value. Round the answer to at least 2 decimal places, if necessary. z= (d)Make the decision.…J2.Newspaper Reading Times A survey taken several years ago found that the average time a person spent reading the local daily newspaper was 10.8 minutes. The standard deviation of the population was 3 minutes. To see whether the average time had changed since the newspaper's format was revised, the newspaper editor surveyed 40 individuals. The average time that the 40 people spent reading the paper was 12.4 minutes. At α=0.10 , is there a change in the average time an individual spends reading the newspaper? Find the 90% confidence interval of the mean. **NOTE** I already have answer for a,b, and c (d)Make the decision. ▼(Choose one) the null hypothesis. (e)Summarize the results. There ▼(Choose one) enough evidence to support the claim that there is a change in the average time an individual spends reading the newspaper. Find the 90% confidence interval of the mean. Round the answers to nearest whole number. <u< (f)Do the results agree?…