Newspaper Reading Times A survey taken several years ago found that the average time a person spent reading the local daily newspaper was 10.8 minutes. The standard deviation of the population was 3 minutes. To see whether the average time had changed since the newspaper's format was revised, the newspaper editor surveyed 40 individuals. The average time that the 40 people spent reading the paper was 12.4 minutes. At α=0.10 , is there a change in the average time an individual spends reading the newspaper? Find the 90% confidence interval of the mean. (a) State the hypothesis and identify the claim with the correct hypothesis
Inverse Normal Distribution
The method used for finding the corresponding z-critical value in a normal distribution using the known probability is said to be an inverse normal distribution. The inverse normal distribution is a continuous probability distribution with a family of two parameters.
Mean, Median, Mode
It is a descriptive summary of a data set. It can be defined by using some of the measures. The central tendencies do not provide information regarding individual data from the dataset. However, they give a summary of the data set. The central tendency or measure of central tendency is a central or typical value for a probability distribution.
Z-Scores
A z-score is a unit of measurement used in statistics to describe the position of a raw score in terms of its distance from the mean, measured with reference to standard deviation from the mean. Z-scores are useful in statistics because they allow comparison between two scores that belong to different normal distributions.
Newspaper Reading Times A survey taken several years ago found that the average time a person spent reading the local daily newspaper was 10.8 minutes. The standard deviation of the population was 3 minutes. To see whether the average time had changed since the newspaper's format was revised, the newspaper editor surveyed 40 individuals. The average time that the 40 people spent reading the paper was 12.4 minutes. At α=0.10
, is there a change in the average time an individual spends reading the newspaper? Find the 90% confidence interval of the mean.
(a) State the hypothesis and identify the claim with the correct hypothesis.
|
:H0
:H1
This hypothesis test is a ▼(Choose one) test. |
|
decimal places, if necessary.
|
▼(Choose one) the null hypothesis.
|
|
|
There ▼(Choose one) enough evidence to support the claim that there is a change in the average time an individual spends reading the newspaper.
|
Find the 90% confidence interval of the mean. Round the answers to nearest whole number.
<u<
| ▼(Choose one) , since the confidence interval does not contain the hypothesized mean of 10.8 minutes, it ▼(Choose one) support the rejection of the null hypothesis and the answer from part 5. |
|
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 3 images
