1.Y is regressed against X1, X2, X3, X4, Xs, and X6. Consider the following test:Ho: B1 = B2 = B3 = 0Hj: one or more of the restrictions under H, does not holdThe sample sizen= 8000. The computer computes the heteroskedasticity-robust F-statistic forthis test. The F-statistic is 2.90. What do you conclude? (R stands for reject and FTR standsfor fail to reject.)A)R Ho at a =0.20R Ho at a == 0.15R Ho at a = 0.10R Ho at a =R Ho at a = 0.01R Ho at a =0.20R Ho at a =0.15R Ho at a = 0.10 | R Ho at a =0.05FTR Ho ata = 0.01FTR Ho atC)R Ho at a =0.20R Ho at a = 0.15R Ho at a = 0.10FTR Ho at%3Da = 0.05= 0.01D)R Ho at a= 0.20R Ho at a = 0.15FTR Ho atFTR Ho atFTR Ho at0.100.05= 0.01a =a =a =E)R Ho at a =0.20FTR Ho atFTR Ho atFTR Ho atFTR Ho at= 0.01a = 0.15FTR Ho ata == 0.10= 0.05a =aF)FTR Họ atFTR Ho atFTR Ho atFTR Ho ata = 0.20a = 0.15a = 0.10a = 0.05a = 0.01B)

Y is regressed against X1, X2, X3, X4, X5, and X6. Consider the following test: Ho: B1 = B2 = B3 = 0 Hj: one or more of the restrictions under Họ does not hold The sample size n = 8000. The computer computes the heteroskedasticity-robust F-statistic fo this test. The F-statistic is 2.90. What do you conclude? (R stands for reject and FTR stands for fail to reject.) R Ho at a = 0.20 R Ho at a = 0.15 R Ho at a = 0.10 R Ho at a = 0.05 R Ho at a = 0.0 R Ho at a = 0.20 R Ho at a = 0.15 R Ho at a = 0.10 R Ho at a = 0.05 FTR Ho at a -001

Y is regressed against X1, X2, X3, X4, X5, and X6. Consider the following test: Ho: B1 = B2 = B3 = 0 Hj: one or more of the restrictions under Họ does not hold The sample size n = 8000. The computer computes the heteroskedasticity-robust F-statistic fo this test. The F-statistic is 2.90. What do you conclude? (R stands for reject and FTR stands for fail to reject.) R Ho at a = 0.20 R Ho at a = 0.15 R Ho at a = 0.10 R Ho at a = 0.05 R Ho at a = 0.0 R Ho at a = 0.20 R Ho at a = 0.15 R Ho at a = 0.10 R Ho at a = 0.05 FTR Ho at a -001

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Which of the following is a benefit of randomization when compared to repetition? A. Randomization takes more time B. Randomization allows for the variation due to machine setup to be captured C. Randomization requires resetting the equipment between tests D. Randomization is less complicated
Test the claim that the proportion of men who own cats is significantly different than the proportion of women who own cats at the 0.2 significance level. The null and alternative hypothesis would be: Ho: M = μF Ho: PM = PF H₁:µm > µF H₁:PM > pF Ho: PM = PF H₁:PM
19. See photo
Need someone to double check my work.
Let a be a random variable representing the percentage of protein content for early bloom alfalfa hay. The average percentage protein content of such early bloom alfalfa should be u = 17.2%. A farmer's co-op is thinking of buying a large amount of baled hay but suspects that the hay is from a later summer cutting with lower protein content. A small amount of hay was removed from each bale of a random sample of 50 bales. The average protein content from the samples was determined by a local agricultural college to be -15.8% with a sample standard deviation of S = 5.3%- At a = .05, does this hay have lower average protein content than the early bloom alfalfa?
Determine if the samples are independent or related. Two formulations of a new whitening soap are compared to their whitening effect. A random sample of 40 potential users of the soap is selected. Each person uses a randomization mechanism to determine which formulation is applied on the left arm so that the other formulation is applied on the right arm. After two weeks, they measured the effect of each formulation.
A high school conducts a dependent sample experiment to test if there is a difference between the number of times students are absent in the fall and winter months. You have data for the following 5 students: STUDENT FALL WINTER 1 2 3 4 5 2 0 1 2 O What do you conclude about this school's absences? (Assume standard a = 0.05) 2 1 2 4 T O There is no difference between the Fall and Winter months. O There is a statistically significant difference between the Fall and Winter months. There is a difference but it is only somewhat statistically significant. There is not enough data to determine if there is a difference in absences.
In a survey of 175 females who recently completed high school, 76% were enrolled in college. In a survey of 150 males who recently completed high school, 72% were enrolled in college. At a = 0.05, can you reject the claim that there is no difference in the proportion of college enrollees between the two groups? Assume the random samples are independent. Complete parts (a) through (e). O A. Ho: P1 #P2 Ha: P1 = P2 O B. Ho: P1 P2 OF. Ho: P1 = P2 O D. Ho: P1 > P2 Ha: P1 SP2 Ha: P1 O B. z 1.96 O D.
Suppose that in a random selection of 100 colored candies, 28% of them are blue. The candy company claims that the percentage of blue candies is equal to 24%. Use a 0.10 significance level to test that claim. H: p>U.24 Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is (Round to two decimal places as needed.) Identify the P-value for this hypothesis test. The P-value for this hypothesis test is (Round to three decimal places as needed.) Identify the conclusion for this hypothesis test. O A. Reject Ho- There is not sufficient evidence to warrant rejection of the claim that the percentage of blue candies is equal to 24% O B. Fail to reject Ho. There is not sufficient evidence to warrant rejection of the claim that the percentage of blue candies is equal to 24% OC. Fail to reject Hn. There is sufficient evidence to warrant rejection of the claim that the percentage of blue candies is equal to 24% O D. Reject Ho. There is sufficient…
Two samples of n = 5 participants each generate the following data. Calculate a t-test score for the difference of these two groups. Group 1 Group 2 2 3 3 3 2 2 2 2 1 2 t(8) = 2.86 t(8) = 2.29 t(8) = 2.5 t(8) = 1.11 Based on the results from the previous question (#7), what is the tcrit and are Group 1 and Group 2 significantly different from each other? Use α = .05, two-tailed test. tcrit = 1.860 Yes, the two groups are significantly different from each other. tcrit = 2.306 Yes, the two groups are significantly different from each other. tcrit = 2.228 Yes, the two groups are significantly different from each other. tcrit = 3.355 No, the two groups are not significantly different from each other.
Two samples of n = 5 participants each generate the following data. Calculate a t-test score for the difference of these two groups. Group 1 Group 2 2 3 3 3 2 2 2 2 1 2 t(8) = 2.86 t(8) = 2.29 t(8) = 2.5 t(8) = 1.11
A survey is conducted to determine if there is a difference in the proportion of students, parents, and teachers who volunteer at least once a month. To investigate, a random sample of 45 students, 25 parents, and 12 teachers was selected from a large high school. The data are displayed in the tables. Observed counts: Expected counts: The researcher would like to test these hypotheses: H0: There is no difference in the distribution of responses among these three populations.Ha: There is a difference in the distribution of responses among these three populations. The conditions for inference are met. What is the value of the chi-square test statistic and what are the degrees of freedom for this test? χ‑2 = 0.19, df = 2χ‑2 = 0.19, df = 5χ‑2 = 0.44, df = 2χ‑2 = 0.44, df = 5