ummary statistics are given for independent simple random samples from two populations. Use the pooled t-test to conduct a left-tailed hypothesis test using 1 = 12, s, = 6, n, = 10, x2 = 20, s2 = 4, n2 = 14 O B. Test statistic: t= - 1.526526 Critical value: - 1.717 0.05 0.001 Do not reject Ho O C. Test statistic: t= -3.929 Critical value: - 2.074 P<0.005 O D. Test statistic: t= - 3.929 Critical value: - 1.717 P<0.005 Reiect He
ummary statistics are given for independent simple random samples from two populations. Use the pooled t-test to conduct a left-tailed hypothesis test using 1 = 12, s, = 6, n, = 10, x2 = 20, s2 = 4, n2 = 14 O B. Test statistic: t= - 1.526526 Critical value: - 1.717 0.05 0.001 Do not reject Ho O C. Test statistic: t= -3.929 Critical value: - 2.074 P<0.005 O D. Test statistic: t= - 3.929 Critical value: - 1.717 P<0.005 Reiect He
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
19. See photo

Transcribed Image Text:Summary statistics are given for independent simple random samples from two populations. Use the pooled t-test to conduct a left-tailed hypothesis test using a signiticance level of & =U.
X = 12, s, = 6, n = 10, x2 20, s2 = 4, n2 = 14
%3D
%3D
%3D
O A. Test statistic: t= -0.916.916
O B. Test statistic: t= - 1.526526
Critical value: - 2.074
Critical value: - 1.717
0.05 <P<0.10
Do not reject Ho
P>0.001
Do not reject Ho
C. Test statistic: t= -3.929
O D. Test statistic: t= - 3.929
Critical value: – 1.717
Critical value: - 2.074
P<0.005
P<0.005
Reject Ho
Reject Ho
Expert Solution

Step 1
Given : n1=10 , n2=14 , X1-bar=12 , X2-bar=20 , s1=6 , s2=4 ,α=0.05
Therefore , the degrees of freedom is given by,
df=n1+n2-2=10+14-2=22
The pooled estimate of the standard deviation is ,
The null and alternative hypothesis is,
Ho : μ1=μ2
H1 : μ1 ˂ μ2
The test left-tailed test.
Our aim is to find the correct option.
Step by step
Solved in 3 steps
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