y 2.82 N 1.0 N 5.0 N 20° 3.0 N
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- 2. A mass of 2.50 kg is at rest at time = 0. Do not consider friction in this problem. Two vector forces are applied to the mass. What is the resulting vector acceleration? F1 = 2.40 i + 1.50 j Newtons. F2 = 5.00 Newtons at an angle of 25.0°with the positive X axis.While two forces act on it, a particle is to move at the constant velocity = (3.58 m/s) -(-3.26 m/s). One of the forces is F1 = (1.88 N) + (-5.85 N). What is the other force? Number i + i j UnitsThe figure shows three blocks attached by cords that loop over frictionless pulleys. Block B lies on a frictionless table; the masses are mA blocks are released, what is the tension in the cord at the right? 6.70 kg, mB 6.20 kg, and mc = 12.0 kg. When the B C Number Units
- A man wants to move a heavy wooden crate (82 kg) across a wooden floor. However, since he is taller than the crate, he must pull it using a rope that makes an angle of 42 degrees with the horizontal. He exerts a force of 312 N as he pulls. What is the Normal Force exerted by the floor on the crate? What is the size of the Friction Force felt by the crate, if the crate moves at a constant speed in a straight line? Imagine that instead the floor is more slick, so that the crate feels a friction force half of what you calculated above. What is the crate’s acceleration?A sled of mass 87 kg is being pushed up a slope with an applied force of 853 N. The slope is inclined with an angle of 34 degrees with respect to the horizontal. The coefficient of friction between the sled and the hill is 0.29. The acceleration of the crate (in m/s²) is:A crate is moving as shown is slowed down by a pushing force P. The force P has a horizontal component of 200 newtons to the left and a vertical component 300 newtons down. The mass of the crate is 90 kgs and the coefficient of kinetic friction is 0.2 and static friction is 0.4. V P What is the magnitude of the acceleration of the crate? Answer in m/s². Use g = 10 m/s². Don't guess! Use the free body diagram method.
- A truck is driving forward with a 90 kg crate on the back. The coefficient of static friction between the crate and truck is µ-0.28. What is the fastest rate the truck could accelerate forward, in m/s², without the crate slipping off the back?A robot pushes a 20-kg box on the horizontal surface as part of the moving job. The force is 35 N to the left shown, and the box does not move. The coefficients of friction between the floor and box are µs = 0.75 and uk = 0.40. What is the minimum pushing force (magnitude only) needed to move the box, in Newtons? Useg = 10 m/s². Your answer needs to have 2 significant figures, including the negative sign in your answer if needed. Do not include the positive sign if the answer is positive. No unit is needed in your answer, it is already given in the question statement.Just like Louis, Maria left a book on the roof of her car before driving away. The mass of the book was 725 grams. The coefficient of static friction between the book and the roof was 0.28. The coefficient of kinetic friction between the book and the roof was 0.23. Maria started her car and drove forward on level ground with an acceleration of 3.6 m/s?. As Maria was driving away with that acceleration, what was the magnitude of the force of friction (in newtons) between the book and the roof of the car?