mov eax,7FFFh cmp eax,8000h
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- Write x86 Assembly code.Convert following x86-64 assembly language function into C code f2: addl %edx, %esi movslq %esi, %rsi movl (%rdi,%rsi,4), %eax retO True O False Question 11 The decoding of 80x86 instructions are simpler than instructions in ARM processors. True O False D Question 12 All instructions of LEGV8 are 32 bits long. O True O False Question 13 In 80x86 assembly language, before calling a function or procedure, you must write a PUSH state address on the Stack. O True O False
- A Program is running on a processor P1 and it has the following parameters: Ic is equal to 20,000,000 instructions Average CPI is 3 cycles/instruction CPU frequency is 500 MHz A new processor P2 is used with the following parameters and the program is executed on this new processor now: Ic is equal to 18,000,000 instructions New average CPI: 3.5 cycles/instruction CPU new frequency: 600 MHz Which processor is faster? Compute the speedup.MICROPROCESSOR FUNDAMENTALS HW 3 Q1. Execute the following program using the following numbers 1. FA+ F4 2. FA + A5 LDI R21,0x R22,0x R23,0XFF DDRB,R23 ; Port B is output LDI LDI OUT ADD R21, R22 BRVC NEXT LDI R23,0XAA PORTB,R23 ; send OXAA to PORTB R21,0x00 OUT LDI ; Clear R21 ΝEXT:SP=1239H, SS=9876H, the physical address is OAAAFH O AAAFOH O 1всобн о O H66666 The instruction JMP BX is a * direct jump True O False O
- A Program is running on a processor Pl and it has the following parameters: Ic is equal to 20,000,000 instructions Average CPI is 3 cycles/instruction CPU frequency is 500 MHz A new processor P2 is used with the following parameters and the program is executed on this new processor now: Ic is equal to 18,000,000 instructions New average CPI: 3.5 cycles/instruction CPU new frequency: 600 MHz Which processor is faster? Compute the speedup.in assembly language, what does the second line of code do? What happens when this code is executed? x WORD 2000h, 3000h, 4000h, 5000h mov ax, [x + (TYPE x)*2 -4]ASM ASSEMBLY LANGUAGE X86 RUN THE CODE AND POST THE SCREENSHOT Write an assembly program to implement the following. sum = 0 i = 0 = 12 varl = 3 var2 = 3 var3 = 0 while ( (i -2)){ if (varl > var3): varl =varl - i else if (var2 < var3): var2 =var2 + j else: var3 = var3+ i sum = varl + var2+ var3 i = i+1 j = j-1 Use short-circuit evaluation Assume that variables are 16-bit signed integers variables You are not allowed to make any logical reduction to the code. You need to implement it the way it is provided. Submit the following: Rename the asm file using your last name as Lastnamel.asm and submit it. Screenshot of the code Then run the code until you reach INVOKE ExitProcess, 0 Then take a screenshot of the watch window showing Sum variable content.
- 10. The register content for an Intel 8086 microprocessor is as follows:CS = 5000H, DS = 6000H, SS = 7000H, SI = 8000H, DI = 9000HBX = 4A1FH, BP = 3000H, AX = 3597H, CX = 19DAH, DX = 8B73HCalculate the physical address of the memory where the operand is stored and thecontents of the memory locations in each of the addresses shown below:a) MOV [BP + 58], AXb) MOV [SI][BX]+2FH, DXc) MOV [DI][SI]+49AH, DXFor the assembly language program and memory map given below, Assembly LOADI RO, -1 Memory Loc Machine Code 00101111 LOADI R1, -3 1 00111101 ADD RO, RO ADDI R1, 2 ADDI RO, 3 SRO RO, R1 ADD R1, RO 7 01000010 3 01110010 01100011 10001100 4 01010010 10000010 SRO RO, RO Trace the program execution for 4 Fetch/Decode/Execute cycles. Enter the register contents in the spaces provided. Assume all registers are initialized to zeros at the start of the execution. Further, assume that execution starts at memory location 0. Note: ALL answers must be given in BINARY not decimal form. RO: R1: PC: IR: OUT: IN:Computer Science Please answer this question in assembly language with .asm extension. The code given in 99Heater.asm file is: ; ===== Heater and Thermostst on Port 03 ==========================; ===== 99Heater.asm ==============================================; ===== Heater and Thermostst on Port 03 ========================== MOV AL,0 ; Code to turn the heater off OUT 03 ; Send code to the heater IN 03 ; Input from Port 03 AND AL,1 ; Mask off left seven bits JZ Cold ; If the result is zero, turn the heater on HALT ; Quit Cold: MOV AL,80 ; Code to turn the heater on OUT 03 ; Send code to the heater END; ================================================================= Fix the program 99Heater.asm so that the temperature will stay at 21 ºC. Please solve the question in assembly language. I will definitely give you THUMBS UP.