There are 24 students enrolled in an introductory statistics class at a small university. As an in-class exercise the students were askedhow many hours of television they watch each week. Their responses, broken down by gender, are summarized in the provided table.Assume that the students enrolled in the statistics class are representative of all students at the university.1 12 12 0 4 10 4 5 5 2 10 10 = 610 3 20 1 6 1 5Male3Eemale 10 3X2 = 4Define the appropriate parameter(s) and state the hypotheses for testing if this sample provides evidence that, on average, malestudents watch more television than female students at this university.O Parameters: µj = mean number of hours of television per week for male students and u2 = mean number of hours oftelevision per week for female students. Hypotheses: Ho: µ1 > µ2 versus Ha: µ1 = µ2.O Parameters: uj = mean number of hours of television per week for male students and u2 = mean number of hours oftelevision per week for female students. Hypotheses: Ho:H1 = µ2 versus Ha: µ1 > µ2.O Parameters: uj = mean number of hours of television per week for male students and u2 = mean number of hours oftelevision per week for female students. Hypotheses: Ho:H1 = µ2 versus Ha: µ1 < µ2.O Parameters: µj = mean number of hours of television per week for male students and u2 = mean number of hours oftelevision per week for female students. Hypotheses: Ho: µi < µ2 versus Ha: µ1 = µ2.2.

The claim is that on average, male students watch more television than females students at this…

Answered: X2 = 4 Define the appropriate…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Your company is evaluating two cloud-based secured data storage services. "Great Sky," the newer service, claims its uploading and downloading speeds are faster than the older service, "Clear and Steady Skies." You need to make a decision based on published access times for both services at different times and for varying file sizes. To make your decision, you purchase two statistical studies from which you discover the average download time for Great Sky is 0.67 sec. per MB and for Clear Steady Skies is 0.84. Additionally, the studies indicate the following sample information: NGS = 60 ncss = 50, SGS = 0.25 and scss = 0.55. Use a .05, and the five step hypothesis testing procedure to make the appropriate decision. Prepare an Excel worksheet properly labeled and well formatted to share with your boss (a very picky person that truly appreciates good looking work product).
The following data were obtained from an independent-measures study comparing three treatment conditions. Treatment 1 2 3 n=6 n=6 n=6 M=1 M=2 M=6 SS=60 SS=65 SS=40 N= 18 G= 54 Sum of squares X^2= 411 Conduct an ANOVA with to determine whether there are any significant differences among the three treatment means. (alpha=.05)
The recommended daily dietary allowance for zinc among males older than age 50 years is 15 mg/day. An article reports the following summary data on intake for a sample of males age 65−74 years: n = 116, x = 12.5, and s = 6.35. Does this data indicate that average daily zinc intake in the population of all males age 65−74 falls below the recommended allowance? (Use ? = 0.05.)State the appropriate null and alternative hypotheses. H0: ? = 15Ha: ? ≠ 15H0: ? = 15Ha: ? > 15 H0: ? = 15Ha: ? ≤ 15H0: ? = 15Ha: ? < 15 Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) z = P-value = State the conclusion in the problem context. Do not reject the null hypothesis. There is not sufficient evidence that average daily zinc intake falls below 15 mg/day.Reject the null hypothesis. There is not sufficient evidence that average daily zinc intake falls below 15 mg/day. Do not reject…
In a simple random sample of 26 small business owners, 25 said that hiring college graduates makes their workplace better. Test the hypothesis that more than 81% of small business owners believe that hiring college graduates makes their workplace better at the 0.05 level. What is the alternative hypothesis? What is the appropriate critical value? State your decision given a test statistic of 1.3.
The mean ±1 sd of ln [calcium intake (mg)] among 25 females, 12 to 14 years of age, below the poverty level is 6.56 ± 0.64. Similarly, the mean ± 1 sd of ln [calcium intake (mg)] among 40 females, 12 to 14 years of age, above the poverty level is 6.80 ± 0.76. 8.2 Test for a significant difference between the variances of the two groups. Find the P value. Do not use excell. Solve the step by step
Show all work/steps! You must use JMP to analyze data.
A repeated-measures study with a sample of n = 16 participants produces a mean difference of MD = 4 with a variance s2 = 64. Use a two-tailed hypothesis test with significance level = .05 to determine whether it is likely that this sample came from a population with MD = 0. State your hypotheses state the critical t-value calculate the t-value for the sample mean difference state your conclusion about the null hypothesis Show all calculations.
A research team conducted a study of VARIABILITY in students' test performance. Researchers assume that individual records are normally distributed with unknown mean and variance. They collected a sample of n = 25 test scores with summaries shown below. Sample Mean = X = 75.2 and Sample SD = S = 15 Estimate the POPULATION VARIANCE with confidence C = 0.99 • Show critical values needed • Evaluate the upper and lower confidence limits. UCL = LCL = Solution
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In an area where there is no radioactive fallout, 1% of newborns show genetic disorders. Genetic disorders were observed in 150 out of 10000 babies born in a year in a region with radioactive fallout as a result of atomic bomb trials.Test whether radioactive fallout increases the rate of genetic defects at α = 0.05 significance level.
A one-sample test is conducted and the APA summary is t(9)=5.02, p<.01. The effect size was r^2=0.89. How would you describe the outcomes of this hypothesis test? A. Failed to reject H0, mainly because of the large sample size B. Failed to reject H0, mainly because of the tiny effect size C. Rejected H0, mainly because of the large effect size D. Rejected H0 mainly because of the large sample size
0.6.3 Question 3 Is the cubic effect significant? How about quadratic and linear effects? Analysis of Variance Table Response: EX Df Sum Sq Mean Sq F value Pr(>F) MET 1 332 332 0.1246 0.7257742 I(MET^2) 1 37504 37504 14.0572 0.0005141 *** I(MET^3) 1 7245 7245 2.7154 0.1065086 Residuals 44 117390 2668 > anova(quadModel) Analysis of Variance Table Response: EX Df Sum Sq Mean Sq F value Pr(>F) MET 1 332 332 0.120 0.7306134 I(MET^2) 1 37504 37504 13.541 0.0006216 *** Residuals 45 124635 2770 --- Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1

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