4b. The conclusion is:O There is sufficient evidence to conclude that not all means are equalO There is insufficient evidence to conclude that not all means are equalO There is sufficient evidence to conclude that all the means are equalOThere is insSufficient evidence to conclude that all the means are equalSubmit QuestionMacBook Air Question 11>x1x2x31614221815181122151021181915201915Test at a = 0.05 to determine if the population means are all the same.1. The null hypothesis is Ho:O µi = µ2 = H3 = H4Oµ1 = µ2 = H3 = H4 = µ5O Hi = µ2 = H32. This is a right tailed test with:d.f.n =and d.f.d =3a. The STS (to 2 decimals) is F =3b. The P-value (to 3 decimals) is:4a. At a = 0.05, the decision is:O Reject HoO Do not reject HoAccept HoO Accept HaMacBook Air

Name: 4b. The conclusion is:O There is sufficient evidence to conclude that
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Description: 4b. The conclusion is:O There is sufficient evidence to conclude that not all means are equalO There is insufficient evidence to conclude that not all means are equalO There is sufficient evidence to conclude that all the means are equalOThere is in

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x1 x2 x3 16 14 22 18 15 18 11 22 15 10 21 18 19 15 20 19 15 Test at a = 0.05 to determine if the population means are all the same. %3D 1. The null hypothesis is Ho: %3D Oµ1 = #2 = H3 = H4 = H5 O µi = H2 == #3 %3D 2. This is a right tailed test with: d.f.n = and d.f.d% = %3D %3D 3a. The STS (to 2 decimals) is F = 3b. The P-value (to 3 decimals) is: 4a. At a = 0.05, the decision is: O Reject Ho Do not reject Ho O Accept Ho Accept Ha

x1 x2 x3 16 14 22 18 15 18 11 22 15 10 21 18 19 15 20 19 15 Test at a = 0.05 to determine if the population means are all the same. %3D 1. The null hypothesis is Ho: %3D Oµ1 = #2 = H3 = H4 = H5 O µi = H2 == #3 %3D 2. This is a right tailed test with: d.f.n = and d.f.d% = %3D %3D 3a. The STS (to 2 decimals) is F = 3b. The P-value (to 3 decimals) is: 4a. At a = 0.05, the decision is: O Reject Ho Do not reject Ho O Accept Ho Accept Ha

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A manufacturer produces crankshafts for an automobile engine. The crankshafts wear after 100,000 miles (0.0001 inch) is of interest because it is likely to have an impact on warranty claims. A random sample of n= 15 shafts is tested and = 2.78. It is known that o = 0.9 and that wear is normally distributed. Question 1: Parameter of interest for this test Question 2: Test Ho: µ = 2.5 versus H1: u + 2.5, a = 0.05 Question 3: What is the power of the test if true u = 3.10 Question 4: Sample size required to detect a true mean of 3.10 if we wanted the power to be at least 0.9? a. Reject Hn. There is evidence to support the claim that the mean wear differs from 2.5 at a = 0.05 Question 1 Question 2 b.ns 15 v Question 3 C.n=24 Question 4 d. 0.7330 e. Mean wear of crankshafts f. Fail to reject Ho- There is no sufficient evidence to support the claim that the mean wear of crankshafts differs from 2.5 at a = 0.05 g 0.2670 >