Independent random samples from normal populations produced the results shown in the table to the right.Assume that the population variances are equal. Complete parts a through d below.a. Calculate the pooled estimate of o².2S. =(Round to four decimal places as needed.)b. Do the data provide sufficient evidence to indicate that μ₂ > μ₁? Test using α = 0.10.What are the null and alternative hypotheses?OA. Ho: H₁-H₂ = 0.10Hai H- Hy 20.10OC. Ho: H₁-H₂=0Ha H-Hz<0What is the test statistic?t=7(Round to two decimal places as needed.)LAILLLInC I'√₁OB. Ho: H₁OD. Ho: H₁-H₂=0Ha: H1 H₂>0ŞH₂ = 0.10Ha: H - Hz≤0.10Vi(1,0)Sample 11.32.91.62.92.8MoreSample 24.42.63.84.1

The below table gives the data of independent random samples from normal populations:Sample 1Sample…

Answered: Independent random samples from normal…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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The nicotine content in cigarettes of a certain brand is normally distributed. The brand advertises that the mean nicotine content of their cigarettes is µ = 1.5, but measurements on a random sample of 100 cigarettes of this brand gave a mean of ?̅= 1.53 and s = 0.95. Is this evidence that the mean nicotine content is actually higher than advertised? 1. State the appropriate null and alternative hypotheses. H0: ? = 1.5 Ha: ? > 1.5 2. Should you use the z or t test? t – do not have sigma 3. Compute the test statistic to test your hypotheses. (report to 2 decimal places) ? = 1.53−1.5 0.95 √100 ⁄ = 0.32 4. Find the appropriate range of p-value for your test. P-value: a. Less than 0.005 b. Between 0.005 and 0.01 c. Between 0.01 and 0.025 d. Between 0.025 and 0.05 e. Greater than 0.05
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Assume that you want to test the claim that the paired smaple data come from a population for which the mean difference is population mean d=0. Compute the value of the t test statistic. Round intermediate calculations to four decimal places as need and final answers to three decimal places as needed x 9 6 7 5 12 y 6 8 3 6 7
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Trap spacing measurements (in meters) for a sample of seven teams of red spiny lobster fisherman are reproduced in the accompanying table. Let u represent the average of the trap spacing measurements for the population of red spiny lobster fisherman. The mean and the standard deviation of the sample measurements are x = 91.4 meters and s = 12.2 meters, respectively. Suppose you want to determine if the true value of µ differs from 95 meters. Complete parts a through h below. μ 94 100 108 97 83 71 87 a. Specify the null and alternative hypotheses for this test. OA. Ho: μ = 95 Ha: μ 95 d. Find the approximate p-value of the test. OD. Ho: μ = 95 H₂:μ #95 a MacBook Pro Next
T-TEST FOR INDEPENDENT MEANS 1. Two types of instruments for measuring the amount of sulfur monoxide in the atmosphere are being compared in an air pollution experiment. It is desired to determine whether the types of instruments yield measurement having the same variability. The following readings were recorded for the instrument. Sulfur Monoxide Instrument A Instrument B 0.86 0.87 0.82 0.74 0.75 0.63 0.61 0.55 0.89 0.76 0.64 0.70 0.81 0.69 0.68 0.57 0.65 0.53 Assuming the population of measurements to be approximately normally distributed, test the null hypothesis using two tailed test at 0.05 level of significance.
Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 4.6 parts/million (ppm). A researcher believes that the current ozone level is at an excess level. The mean of 14 samples is 4.9 ppm with a variance of 1.2 Does the data support the claim at the 0.01 level? Assume the population distribution is approximately normal. Step 2 of 5 : Find the value of the test statistic. Round your answer to three decimal places.
Question 1 Mark A disability insurance policy is sold to an individual earning $60,000 per year. The probability of partial disability follows a uniform distribution over the interval [o, 60,000]. The policy only pays if the loss is greater than 20% of the salary. What is the standard deviation of the payout? A $12,000 B $13,900 $15,200 D $17,300 E $19,000 Grade & Review >
2. Two kinds of bumper guards, six of each kind, were mounted on a certain make of compact car. Each car was then run into a concrete wall at 5 miles per hour and the costs of repairs (in dollars) was recorded. Summary of the data is shown below. n = 6 i = 144 si = 363.20 n =6 i = 149 si = 202.00 Test at the 0.02 level of significance whether it is reasonable to assume that the two populations sampled have equal variances.
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